的Android - 發送通過POST方法容易

package demo.com.mysqldbdemo; 

import android.content.Context; 
import android.os.AsyncTask; 
import android.widget.Toast; 

import java.io.BufferedWriter; 
import java.io.IOException; 
import java.io.InputStream; 
import java.io.OutputStream; 
import java.io.OutputStreamWriter; 
import java.net.MalformedURLException; 
import java.net.URL; 
import java.net.URLEncoder; 

import javax.net.ssl.HttpsURLConnection; 

/** 
* Created by Ahmadzai on 7/10/2017. 
*/ 

public class BackgroundTask extends AsyncTask<String, Void, String> { 

    Context ctx; 
    BackgroundTask(Context ctx) 
    { 
     this.ctx = ctx; 
    } 

    @Override 
    protected void onPreExecute() { 
     super.onPreExecute(); 
    } 

    @Override 
    protected String doInBackground(String... params) { 
     String reg_url = "http://192.168.8.100:8081/webapp/register.php"; 
     String login_url = "http://localhost/webapp/login.php"; 
     String method = params[0]; 
     if (method.equals("register")) 
     { 
      String name = params[1]; 
      String user_name = params[2]; 
      String user_pass = params[3]; 

      try { 
       URL url = new URL(reg_url); 
       HttpsURLConnection httpsURLConnection = (HttpsURLConnection) url.openConnection(); 
       httpsURLConnection.setRequestMethod("POST"); 
       httpsURLConnection.setDoOutput(true); 
       OutputStream OS = httpsURLConnection.getOutputStream(); 
       BufferedWriter bufferedWriter = new BufferedWriter(new OutputStreamWriter(OS,"UTF-8")); 
       String data = URLEncoder.encode("user","UTF-8") + "=" +URLEncoder.encode(name,"UTF-8")+"&"+ 
         URLEncoder.encode("user_name","UTF-8") + "=" +URLEncoder.encode(user_name,"UTF-8")+"&"+ 
         URLEncoder.encode("user_pass","UTF-8") + "=" +URLEncoder.encode(user_pass,"UTF-8"); 
       bufferedWriter.write(data); 
       bufferedWriter.flush(); 
       bufferedWriter.close(); 
       OS.close(); 

       InputStream IS = httpsURLConnection.getInputStream(); 
       IS.close(); 
       return "Registration succeed ...."; 

      } catch (MalformedURLException e) { 
       e.printStackTrace(); 
      } catch (IOException e) { 
       e.printStackTrace(); 
      } 
     } 
     return null; 
    } 

    @Override 
    protected void onProgressUpdate(Void... values) { 
     super.onProgressUpdate(values); 
    } 

    @Override 
    protected void onPostExecute(String result) { 
     Toast.makeText(ctx,result,Toast.LENGTH_LONG).show(); 
    } 
}

我想數據插入MySQL表HTTP參數，如以下代碼沒有任何錯誤，但我按在接口寄存器按鈕應用程序停止運行時，欲調試它運行的應用程序，直到「HttpsURLConnection httpsURLConnection =（HttpsURLConnection）url.openConnection（）;」之後的代碼行停止調試。任何人都可以在這方面幫助我嗎？我一直在使用stackoverflow的答案，但這是我第一次嘗試提問，抱歉給您帶來不便。的Android - 發送通過POST方法容易

來源

2017-07-10 Tariq

什麼是您的logcat的說？ –

我建議你閱讀關於改造 – DeKaNszn

我打賭類拋出異常，因爲你的URL不代表'HTTPS'連接。 –

開始使用retrofit這是最好的Android

來源

2017-07-10 13:43:47 Alex

如果你推薦一個工具，也請描述如何使用該工具解決手頭的問題。 –

謝謝，它已經解決了。 – Tariq

的Android - 發送通過POST方法容易

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