當文件名是一個變量時批處理文件來重命名文件

Question

我在這裏已經找到了這個基本代碼，並且正在使用它來移動，然後重新命名我知道文件名的文件。但是，現在我想移動一個文件，其中的文件名是一個參數。

當我運行此代碼時，它將使用當前日期和時間重命名文件夾。我如何獲得它來重命名文件夾中的變量文件名？我添加了暫停來嘗試排查發生的事情。

Echo Off 
SET SiteName=%~1 
SET FileDate=%~2 
SET File=%SiteName%%FileDate% 


IF Not EXIST C:\Users\Administrator\Documents\~Withdrawal_Report\%File% GOTO DoNothing 

copy C:\Users\Administrator\Documents\~Withdrawal_Report\%File% C:\Users\Administrator\Documents\~Withdrawal_Report_Archive\%File% 


ren C:\Users\Administrator\Documents\~Withdrawal_Report_Archive\%File% %SiteName%-%date:~4,2%-%date:~7,2%-%date:~10,4%_@_%time:~0,2%h%time:~3,2%m%time:~6,2%s%.csv 
ren C:\Users\Administrator\Documents\~Withdrawal_Report_Archive\%File% %SiteName%-%date:~4,2%-%date:~7,2%-%date:~10,4%_@_%time:~1,1%h%time:~3,2%m%time:~6,2%s%.csv 


del C:\Users\Administrator\Documents\~Withdrawal_Report\%File% 
pause 

:DoNothing 
Exit 

Answer 1

嘗試使用雙引號，像這樣：

Echo Off 
SET "SiteName=%~1" 
SET "FileDate=%~2" 
SET "File=%SiteName%%FileDate%" 


IF Not EXIST "C:\Users\Administrator\Documents\~Withdrawal_Report\%File%" GOTO DoNothing 

copy "C:\Users\Administrator\Documents\~Withdrawal_Report\%File%" "C:\Users\Administrator\Documents\~Withdrawal_Report_Archive\%File%" 

ren "C:\Users\Administrator\Documents\~Withdrawal_Report_Archive\%File%" "%SiteName%-%date:~4,2%-%date:~7,2%-%date:~10,4%_@_%time:~0,2%h%time:~3,2%m%time:~6,2%s%.csv" 
ren "C:\Users\Administrator\Documents\~Withdrawal_Report_Archive\%File%" "%SiteName%-%date:~4,2%-%date:~7,2%-%date:~10,4%_@_%time:~1,1%h%time:~3,2%m%time:~6,2%s%.csv" 


del "C:\Users\Administrator\Documents\~Withdrawal_Report\%File%" 
pause 

:DoNothing 
Exit 

而且，你要重命名兩次相同的文件，據我可以告訴。之前做過這個工作嗎？