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我正在codeigniter中的form_dropdown()上工作。更改form_dropdown codeigniter
我有表countrystate(ID,COUNTRYNAME,Statename的)
我填充填充上form_dropdown( 'fd_country')COUNTRYNAME &。
現在我想基於選定的國家名顯示州名。請幫忙。
我正在codeigniter中的form_dropdown()上工作。更改form_dropdown codeigniter
我有表countrystate(ID,COUNTRYNAME,Statename的)
我填充填充上form_dropdown( 'fd_country')COUNTRYNAME &。
現在我想基於選定的國家名顯示州名。請幫忙。
看到像我這樣做是 http://help.webhostel.org/h14682223
控制器代碼
public function index() {
$this->load->database();
$this->db->select('countryname');
$this->db->group_by('countryname');
$query = $this->db->get('country');
foreach($query->result() as $item)
$countries[$item->countryname] = $item->countryname;
$data = array('department' => $countries);
$this->load->helper('form');
$this->load->view('welcome_message', $data);
}
public function get_subdepartment() {
$this->load->database();
$this->load->helper('form');
$states = array();
if($this->input->post('dep_selected')) {
$this->db->select('countrystate');
$this->db->where(array('countryname' => $this->input->post('dep_selected')));
$query = $this->db->get('country');
foreach($query->result() as $item)
$states[$item->countrystate] = $item->countrystate;
}
$output = form_dropdown('subdept', $states);
echo $output;
}
模板部分。
<script type="text/javascript">
function get_subdepartment() {
var dep_selected = $('select[name=txtDept]').val();
$.ajax({
data: {
dep_selected: dep_selected,
},
type: 'POST',
url: '/welcome/get_subdepartment',
success: function(data){
console.log(data);
$('.subdepartment').html(data);
}
})
}
</script>
<div id="container">
<h1>Welcome to CodeIgniter</h1>
<div id="body">
<? echo form_open("addEmployee"); $newEmp = array('name' => 'newEmployee', 'id' => 'newEmployee', 'value' => set_value('ne')); ?>
<div for='newEmp'><input type="text" name="txtEmpName" id="txtEmpName" maxlength="25" /></div>
<div for='newEmp'>
<? echo form_dropdown($name = 'txtDept',$Options = $department, array($this->input->post('txtDept')),'onChange="get_subdepartment()"'); ?>
</div>
<div for='newEmp' class="subdepartment"></div>
<? echo form_submit('do_submit', 'Submit'); ?>
<? echo form_close(); ?>
</div>
我使用<? echo form_open(); ?>和上面的代碼相同但沒有結果。還有<? form_submit(參數)?>請指導 –
我已更改模板部分。現在看。如果它沒有工作 - 顯示模板的所有部分 –
沒有數據發佈代碼爲:<? echo form_open(「addEmployee」); $ newEmp = array('name'=>'newEmployee','id'=>'newEmployee','value'=> set_value('ne')); ?>