2015-03-19 63 views
-1

我的模型沒有插入我的視圖中選擇的修改和訪問數據。如果我的視圖上的選擇選項是選擇選項1,即使選擇了1,也會插入值0。不知道爲什麼在模型上或查看它不插入正確的?模型不插入選擇選項

每個控制器都有自己的修改和訪問選擇選項,我希望能夠插入如果選擇1啓用或0 disbale?

如何使兩個選擇選項與我的模型一起工作,以便正確插入所選內容。

型號功能

<?php 

class Model_user_group extends CI_Model { 

public function addUserGroup() { 

    $name = $this->input->post('name'); 
    $controllers = $this->input->post('controller'); 
    $access = $this->input->post('access'); 
    $modify = $this->input->post('modify'); 

    for($i=0;$i<count($controllers);$i++) { 

    $data = array(
     'name' => strtolower($name), 
     'controller' => $controllers[$i], 
     'access' => $access, 
     'modify' => $modify 
    ); 


    $this->db->insert($this->db->dbprefix . 'user_group', $data); 

    } 

} 

查看

<?php echo Modules::run('admin/common/header/index');?> 

<div id="wrapper"> 
<?php echo Modules::run('admin/common/menu/index');?> 
<div id="page-wrapper" > 
<div id="page-inner"> 

<div class="panel panel-default"> 
<div class="panel-heading clearfix"> 
<div class="pull-left" style="padding-top: 7.5px"><h1 class="panel-title"><?php echo $title;?></h1></div> 
<div class="pull-right"> 
<a href="<?php echo base_url('admin/users_group');?>" class="btn btn-primary">Cancel</a> 
<button type="submit" onclick="submit()" class="btn btn-primary">Save</button> 
</div> 
</div> 
<div class="panel-body"> 

<?php echo validation_errors('<div class="alert alert-warning text-center">', '</div>'); ?> 

<?php $data = array('class' => 'form-horizontal', 'id' => 'form-users-group');?> 
<?php echo form_open_multipart('admin/users_group_add', $data);?> 

<div class="form-group"> 
<?php $data = array('class' => 'col-sm-2');?> 
<?php echo form_label('User Group Name', 'name', $data);?> 
<div class="col-sm-10"> 
<?php $data1 = array('id' => 'name', 'name' => 'name', 'class' => 'form-control', 'value' => set_value('name'));?> 
<?php echo form_input($data1);?> 
</div> 
</div> 

<table class="table table-striped table-bordered"> 
<thead> 
    <tr> 
     <td>Controller Name</td> 
     <td>Access</td> 
     <td>Modify</td> 
    </tr> 
</thead> 
<?php foreach ($controllers as $controller) {?> 
<tbody> 
<tr> 
<td> 
<?php echo ucfirst(str_replace("_"," ", $controller));?> 
<input type="hidden" name="controller[]" value="<?php echo $controller;?>" /> 
</td> 
<td> 
<select name="access" class="form-control"> 
    <option value="0">Disabled</option> 
    <option value="1">Enabled</option> 
</select> 
</td> 
<td> 
<select name="modify" class="form-control"> 
    <option value="0">Disabled</option> 
    <option value="1">Enabled</option> 
</select> 
</td> 
</tr> 
</tbody> 
<?php } ?> 
</table> 

<?php echo form_close();?> 
</div> 
</div> 

</div><!-- # Page Inner End --> 
</div><!-- # Page End --> 

</div><!-- # Wrapper End --> 
<?php echo Modules::run('admin/common/footer/index');?> 
+0

是什麼原因下跌票? – user4419336 2015-03-19 04:40:04

回答

1

你的視圖文件似乎可以訪問和修改每個控制器選項。但是你的輸入名稱是相同的。所以$ access和$ modify的值是最後一個輸入值。你可以解決這個way.Give訪問和修改輸入的名稱作爲數組

<select name="access[]" class="form-control"> 
... 
<select name="modify[]" class="form-control"> 

現在你的模型

$name = $this->input->post('name'); 
$controllers = $this->input->post('controller'); 
$accesses = $this->input->post('access'); 
$modifies = $this->input->post('modify'); 

for($i=0;$i<count($controllers);$i++) { 

    $data = array(
    'name' => strtolower($name), 
    'controller' => $controllers[$i], 
    'access' => $accesses[$i], 
    'modify' => $modifies[$i] 
    ); 


    $this->db->insert($this->db->dbprefix . 'user_group', $data); 

} 

希望你能理解和解決您的問題

+0

所有工作現在感謝。 – user4419336 2015-03-19 04:38:56