Question

此腳本不斷返回「其他」響應。爲什麼我的病情不斷失敗：

<?php 

    $fileName = $_GET['far_sighted_michael_pitluk.mp3']; 
    $fileDisplayName = "Far-Sighted"; 

    // Fetch the file info. 
    $filePath = 'http://michaelpitluk.com/audio/far_sighted_michael_pitluk.mp3'; 

    if(file_exists($filePath)) { 
     $fileName = basename($filePath); 
     $fileSize = filesize($filePath); 

     // Output headers. 
     header("Cache-Control: private"); 
     header("Content-Type: application/stream"); 
     header("Content-Length: ".$fileSize); 
     header("Content-Disposition: attachment; filename=".$fileDisplayName); 

     // Output file. 
     readfile ($filePath);     
     exit(); 
    } 
    else { 
     die('The provided file path is not valid.'); 
    } 
?> 

我不明白路徑有什麼問題。

Answer 1

如果您$filePath開始與http://您可能需要啓用allow_url_fopen。 PHP Manual。

嘗試

ini_set("allow-url-fopen", true); 
// Fetch the file info. 
$filePath = 'http://michaelpitluk.com/audio/far_sighted_michael_pitluk.mp3'; 

編輯： 試試這個：

<?php 

    $fileName = $_GET['far_sighted_michael_pitluk.mp3']; 
    $fileDisplayName = "Far-Sighted.mp3"; 

    // Fetch the file info. 
    $filePath = '../audio/far_sighted_michael_pitluk.mp3'; 

    if(file_exists($filePath)) { 
     $fileName = basename($filePath); 
     $fileSize = filesize($filePath); 

     // Output headers. 
     header("Cache-Control: private"); 
     header("Content-Type: audio/mpeg, audio/x-mpeg, audio/x-mpeg-3, audio/mpeg3"); 
     header("Content-Length: ".$fileSize); 
     header("Content-Disposition: attachment; filename=".$fileDisplayName); 

     // Output file. 
     readfile ($filePath);     
     exit(); 
    } 
    else { 
     die('The provided file path is not valid.'); 
    } 
?> 

Answer 2

fileexist（）函數的路徑到您的文件你的主機，而不是一個完整的URL 上嘗試這個

$filePath = 'audio/far_sighted_michael_pitluk.mp3';