1
我正在嘗試編寫一個讀取多個文件並逐行比較它們的程序。要讀取的文件數量取自用戶,文件預計採用「input1.txt」,「input2.txt」等形式。當讀取nextLine()時出現「行不可用」錯誤;從文件掃描程序
當我嘗試運行我的代碼時,得到一個「NoSuchElementException」,告訴我Scanner.nextLine()行:行不可用。這是在50行,這是:jthLine.add(myScanners.get(k - 1).nextLine());
。我無法弄清楚爲什麼不會有一行讀取,因爲這已經在一個以最少行數爲界的循環中完成了。
任何幫助表示讚賞!這裏是我的代碼:
// Compares n input files, prints the lines that are not equal in all.
import java.util.Scanner;
import java.io.*;
import java.util.ArrayList;
import java.util.Collections;
public class CompareFiles {
public static void main(String[] args) throws IOException {
Scanner consoleScanner = new Scanner(System.in);
int numberOfFiles;
System.out.println("Please enter how many files are there. The" +
"file names should be like: input1.txt input2.txt, etc.");
numberOfFiles = consoleScanner.nextInt();
ArrayList<Scanner> myScanners = new ArrayList<Scanner>();
for (int k = 1; k <= numberOfFiles; k++)
myScanners.add(new Scanner(new File("input" + k + ".txt")));
// Find the file line counts.
ArrayList<Integer> lineCounts = new ArrayList<Integer>();
Integer lineCount;
String increment;
for (int i = 1; i <= numberOfFiles; i++) {
lineCount = 0;
while (myScanners.get(i - 1).hasNext()) {
increment = myScanners.get(i - 1).nextLine();
lineCount++;
}
lineCounts.add(lineCount);
}
// Find the minimum file count.
int minLineCount = Collections.min(lineCounts);
// Compare files until minLineCount line by line
// println all the unmatching lines from all files
// jthLine holds the incremented lines from all files
ArrayList<String> jthLine = new ArrayList<String>();
boolean allMenAreTheSame;
for (int j = 1; j <= minLineCount; j++) {
allMenAreTheSame = true; // are all jth lines the same?
for (int k = 1; k <= numberOfFiles; k++) {
jthLine.add(myScanners.get(k - 1).nextLine());
if (!jthLine.get(0).equals(jthLine.get(k)))
allMenAreTheSame = false;
}
if (!allMenAreTheSame) {
System.out.println();
System.out.println("Line number " + j + " is not the same" +
"across all files, printing the lines:");
for (int k = 1; k <= numberOfFiles; k++) {
System.out.println("File: \"input" + k + ".txt\":");
System.out.println(jthLine.get(k - 1));
}
}
jthLine.clear();
}
}
}
哦,快點!謝謝。 –