圍捕十進制到下一個數字在PHP

Question

我期待任何小數四捨五入到下一個數字。像1.199 答案應該是或類似1.99也應該

這是迄今爲止我發現了什麼

echo(round(1.4,0,PHP_ROUND_HALF_UP) . "<br>"); 
echo(round(-1.4,0,PHP_ROUND_HALF_UP) . "<br>"); 
//Answer = 1 
//Answer = -1 

echo(round(1.4,0,PHP_ROUND_HALF_DOWN) . "<br>"); 
echo(round(-1.4,0,PHP_ROUND_HALF_DOWN) . "<br>"); 
//Answer = 1 
//Answer = -1 

echo(round(1.4,0,PHP_ROUND_HALF_EVEN) . "<br>"); 
echo(round(-1.4,0,PHP_ROUND_HALF_EVEN) . "<br>"); 
//Answer = 1 
//Answer = -1 

echo(round(1.4,0,PHP_ROUND_HALF_ODD) . "<br>"); 
echo(round(-1.,0,PHP_ROUND_HALF_ODD)); 
//Answer = 1 
//Answer = -1 

Answer 1

使用ceil

echo ceil(1.9999); // 2 
echo ceil(1.001); // 2 

Answer 2

，如果你想接下來數使用ceil

echo ceil(1.99); //Output = 2 

Answer 3

echo ceil(1.199); 

，除此之外，該

Answer 4

使用此代碼

echo ceil(1.9999); // Output will be 2 

如需詳細資料請參閱本https://www.w3schools.com/php/func_math_ceil.asp