如何在bash腳本中超時？

Question

可能重複：
Timeout a command in bash without unnecessary delay

原來這就是我想要做的事 -

for test in `ls Tests`; do 

for file in `ls FileFolder`; do 

output=`python devcap $test $file` 

echo $test $file $output >>result.txt 

done 

done 

如何超時的$輸出，如果它需要比說長5秒鐘，並移動到下一個$文件？

我可以將stderr重定向到result.txt嗎？

Answer 1

試試這個：

for test in `ls Tests`; do 

for file in `ls FileFolder`; do 

output=`python devcap $test $file` 

sleep 5 

echo $test $file $output >>result.txt 

done 

done