1
我正在使用iOS Parse Framework。我創建一個用戶是這樣的:修改當前用戶的ACL
PFUser *user = [PFUser user];
user.username = self.userNameTextField.text;
user.password = self.passwordTextField.text;
user.email = self.emailTextField.text;
[user signUpInBackgroundWithBlock:^(BOOL succeeded, NSError *error) {
if (!error) {
//user saved
} else {
NSString *errorString = [error userInfo][@"error"];
// Show the errorString somewhere and let the user try again.
}
}];
但是,如果我用這個代碼:
PFQuery *query = [PFUser query];
[query findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) {
if (!error) {
// The find succeeded.
NSLog(@"Successfully retrieved %d scores.", objects.count);
// Do something with the found objects
for (PFUser *user in objects) {
NSLog(@"User:%@",user);
}
} else {
// Log details of the failure
NSLog(@"Error: %@ %@", error, [error userInfo]);
}
}];
這個工程,並列出所有用戶名。我希望每個用戶只能得到他的信息而不能獲得其他信息。我怎麼能實現呢?我試着做以下幾點:
PFACL *userACL = [PFACL ACLWithUser:[PFUser currentUser]];
[userACL setPublicReadAccess:NO];
[userACL setPublicWriteAccess:NO];
user.ACL = userACL;
,但它不會讓我,所以我基本上想要做的,不知道怎麼,我不希望用戶能夠從獲取所有用戶'用戶'表我希望每個用戶只能訪問自己的用戶對象。
爲什麼它不會讓你?解析返回一個錯誤? –