加處理程序來運行服務器是一個常見的模式,但該文件並不清楚在所有(在「嵌入碼頭」教程的所有實例啓動服務器後的配置)AFAIK人的是以下這些方法:使用HandlerCollection(布爾mutableWhenRunning)構造函數添加
1)/移除處理程序
2)添加並啓動手明確指出
我觀察到#2在Jetty 9.1.4中並不需要,但是它在Jetty 9.2.14之後(隨後這些版本號被Maven選爲澤西依賴關係,這與這個問題完全無關。 )例如:
// after server creation ...
ContextHandlerCollection contextHandlerCollection = new ContextHandlerCollection();
jettyServer.setHandler(contextHandlerCollection);
jettyServer.start();
// ...
ServletContextHandler newSCH= new ServletContextHandler(ServletContextHandler.SESSIONS);
newSCH.setResourceBase(System.getProperty("java.io.tmpdir"));
newSCH.setContextPath("/servlets");
ServletHolder newHolder = new SwServletHolder(servlet);
newSCH.addServlet(newHolder, "/*");
contextHandlerCollection.addHandler(newSCH);
try {
newSCH.start(); // needed from about 9.2
} catch (Exception e) {
logger.info("Exception starting ServletContextHandler for Jetty", e);
}
爲了增加這樣的SOAP上下文是 「用於工作」 上9.1.4(上9.2.14代碼它報告404):
import java.lang.reflect.Method;
import java.net.InetSocketAddress;
import javax.jws.WebService;
import javax.xml.ws.Endpoint;
import org.eclipse.jetty.http.spi.JettyHttpServerProvider;
import org.eclipse.jetty.http.spi.HttpSpiContextHandler;
import org.eclipse.jetty.http.spi.JettyHttpContext;
import org.eclipse.jetty.http.spi.JettyHttpServer;
import org.eclipse.jetty.server.Server;
import org.eclipse.jetty.server.handler.ContextHandlerCollection;
import com.sun.net.httpserver.HttpContext;
public class JettyJaxWs {
public static void main(String[] args) throws Exception {
Server server = new Server(7777);
ContextHandlerCollection contextHandlerCollection = new ContextHandlerCollection();
server.setHandler(contextHandlerCollection);
server.start();
HttpContext context = buildOrig(server, "/ws");
MyWebService ws = new MyWebService();
Endpoint endpoint = Endpoint.create(ws);
endpoint.publish(context);
// access wsdl on http://localhost:7777/ws/MyWebService?wsdl
}
@WebService
public static class MyWebService {
public String hello(String s) {
return "hi " + s;
}
}
public static HttpContext buildOrig(Server server, String contextString) throws Exception {
JettyHttpServerProvider.setServer(server);
return new JettyHttpServerProvider().createHttpServer(new InetSocketAddress(7777), 5).createContext(contextString);
}
後來,我必須爲最後一種方法做這件事(不確定是否有更好的方法):
public static HttpContext buildNew(Server server, String contextString) {
JettyHttpServer jettyHttpServer = new JettyHttpServer(server, true);
JettyHttpContext ctx = (JettyHttpContext) jettyHttpServer.createContext(contextString);
try {
Method method = JettyHttpContext.class.getDeclaredMethod("getJettyContextHandler");
method.setAccessible(true);
HttpSpiContextHandler contextHandler = (HttpSpiContextHandler) method.invoke(ctx);
contextHandler.start();
} catch (Exception e) {
e.printStackTrace();
}
return ctx;
}
來源
2016-07-22 15:27:50
DBE