我是JavaScript新手,可能會嘗試做一些愚蠢的事情,因爲一小時的搜索結果並未導致任何示例。將數組作爲參數傳遞給對象
我努力學習的對象,所以我做了一個構造函數是這樣的:
//generic object
function clip(name, xposition, firstVisibleFrame, lastVisibleFrame, playStart, playEnd, defaultFrame, seqLoopStart, seqLoopEnd, backStateLevel){
this.name = name;
this.xposition = xposition;
this.outlinesArray =[];
this.firstVisibleFrame = firstVisibleFrame;
this.lastVisibleFrame = lastVisibleFrame;
this.outlinePath = ("outlines/" +this.name +"_");
this.playStart = playStart;
this.playEnd = playEnd;
this.defaultFrame = defaultFrame;
this.seqLoopStart = seqLoopStart;
this.seqLoopEnd = seqLoopEnd;
this.backStateLevel = backStateLevel;
};
接下來,我將創建一個對象的新實例的東西,如:
livingroomTable = new clip("livingroomTable");
.. 。但現在我真的被卡住,因爲我應該傳遞給函數的下一個參數實際上是一個包含數百個值的巨大數組。
我試圖將數組放入參數中,像這樣:
livingroomTable = new clip("livingroomTable", [value1, value2, value3, value4, value5 and so on and so on]);
但這給了我一個語法錯誤。
我不想讓這個數組成爲一個全局變量。作爲函數調用參數的一部分傳遞一個值數組的正確語法是什麼?
編輯:
下面是實際的代碼:
//generic object
function clip(name, xposition, firstVisibleFrame, lastVisibleFrame, playStart, playEnd, defaultFrame, seqLoopStart, seqLoopEnd, backStateLevel){
this.name = name; //objektin nimi tulee funktion kutsusta
this.xposition = xposition;
this.outlinesArray =[];
this.firstVisibleFrame = firstVisibleFrame;
this.lastVisibleFrame = lastVisibleFrame;
this.outlinePath = ("outlines/" +this.name +"_");
this.playStart = playStart;
this.playEnd = playEnd;
this.defaultFrame = defaultFrame;
this.seqLoopStart = seqLoopStart;
this.seqLoopEnd = seqLoopEnd;
this.backStateLevel = backStateLevel;
};
livingroomTable = new clip(
"livingroomTable", //name
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//xposition
352, //firstVisibleFrame
545, //lastVisibleFrame
2058, //playStart
2304, //playEnd
2175, //defaultFrame
-1000, //seqLoopStart
-1000, //seqLoopEnd
1 //backStateLevel
);
Hmmmm其實我覺得我的問題是在陣列權的最後的分號? :D
如果你得到一個* SyntaxError *,你需要顯示你的實際代碼來獲得幫助。 – 2012-07-31 01:08:45
好吧,但陣列將是巨大的:D – 2012-07-31 01:09:52
http://www.jslint.com/可能會幫助 – valentinas 2012-07-31 01:10:13