通過使用mysql的組總和

-1

我有三個表financial_year，house_details，consumer_details。我需要按年份和子收入獲得每個稅收組的總和。我的表，查詢是在這個環節：sqlfiddle 通過使用mysql的組總和

獲得結果：

Name house_number address subincome financial_year gtax htax LTAX 
-------------------------------------------------------------------------- 
Bala 22   Mumbai Garbage tax 2015-2016  200 NULL NULL 
Bala 22   Mumbai Garbage tax 2016-2017  250 NULL NULL 
Bala 22   Mumbai House tax 2015-2016  NULL 0  NULL 
Bala 22   Mumbai House tax 2016-2017  NULL 145 NULL 
Bala 22   Mumbai Light tax 2015-2016  NULL NULL 510 
Bala 22   Mumbai Light tax 2016-2017  NULL NULL 200

期待結果：

Name house_number address gtax htax LTAX 
-------------------------------------------------------- 
Bala 22    Mumbai  450  145  710

來源

2017-12-18 Kannan K

將您的結果粘貼爲文本而不是圖像。有些人看不到圖像。 –

鏈接是圖像而不是sqlfiddle。 –

@ P.Salmon是的，我更新請檢查。 –

您正在尋找條件彙總備註此解決方案僅適用於每個財政年度的房屋詳細信息中的每個子分類（稅類型）的條目。

SELECT c.consumer_name as Name, c.house_number, c.address, 
sum(CASE WHEN h.subincome = 'Garbage tax' THEN f.garbage_tax else 0 end) - 
sum(CASE WHEN h.subincome = 'Garbage tax' THEN h.rupees else 0 END) as gtax, 
sum(CASE WHEN h.subincome = 'House tax' THEN f.house_tax else 0 end) - 
sum(CASE WHEN h.subincome = 'House tax' THEN h.rupees else 0 END) as htax, 
sum(CASE WHEN h.subincome = 'Light tax' THEN f.light_tax else 0 end) - 
sum(CASE WHEN h.subincome = 'Light tax' THEN h.rupees else 0 END) as LTAX 
from house_details h 
INNER JOIN financial_year f ON h.financial_year = f.year AND h.house_id = f.house_number 
INNER JOIN consumer_details c ON h.house_id = c.house_number AND h.financial_year != '2017-2018' 
group by c.consumer_name , c.house_number, c.address

結果

+------+--------------+---------+------+------+------+ 
| Name | house_number | address | gtax | htax | LTAX | 
+------+--------------+---------+------+------+------+ 
| Bala | 22   | Mumbai | 450 | 145 | 710 | 
+------+--------------+---------+------+------+------+ 
1 row in set (0.03 sec)

如果不能保證會有在每一個財政年度，則該解決方案已經從應付稅款表驅動，每subincome一個條目（財政年度）這在我看來是設計得很差，不靈活並且強制次優解決方案

select c.consumer_name as Name, s.house_number, c.address, 
     sum(case when subincome = 'garbage tax' then taxdue else 0 end) - sum(case when subincome = 'garbage tax' then taxpaid else 0 end) as gtax, 
     sum(case when subincome = 'house tax' then taxdue else 0 end) - sum(case when subincome = 'house tax' then taxpaid else 0 end) as htax, 
     sum(case when subincome = 'light tax' then taxdue else 0 end) - sum(case when subincome = 'light tax' then taxpaid else 0 end) as ltax 
from 
(
SELECT F.`house_number`, F.`year`, F.`house_tax` taxdue, F.`createdAt`, F.`updatedAt`,ifnull(h.subincome,'house_tax') subincome,ifnull(H.RUPEES,0) taxpaid 
FROM FINANCIAL_YEARS F 
LEFT JOIN house_details H ON H.HOUSE_ID = F.HOUSE_NUMBER AND H.SUBINCOME = 'house tax' and f.year = h.financial_year 
#where f.house_number = 22 
union all 
SELECT F.`house_number`, F.`year`, F.`light_tax`, F.`createdAt`, F.`updatedAt`,ifnull(h.subincome,'light tax'),ifnull(H.RUPEES,0) 
FROM FINANCIAL_YEARS F 
LEFT JOIN house_details H ON H.HOUSE_ID = F.HOUSE_NUMBER AND H.SUBINCOME = 'light tax' and f.year = h.financial_year 
#where f.house_number = 2 
union all 
SELECT F.`house_number`, F.`year`, F.`garbage_tax`, F.`createdAt`, F.`updatedAt`,ifnull(h.subincome,'garbage tax'),ifnull(H.RUPEES,0) 
FROM FINANCIAL_YEARS F 
LEFT JOIN house_details H ON H.HOUSE_ID = F.HOUSE_NUMBER AND H.SUBINCOME = 'garbage tax' and f.year = h.financial_year 
#where f.house_number = 2 
) s 
join consumer_details c on s.house_number = c.house_number 
where s.year <> '2017-2018' 
group by c.consumer_name , s.house_number, c.address

來源

2017-12-18 10:33:32

謝謝三文魚。 –

請檢查更新的答案。順便說一句，你可能想改變一些你的表和列的名字，使它們更有意義。 –

你能解釋一下用什麼納稅領域。 –

試試這個，它會給確切的結果是你想要的，我只是創建一個驅動器表然後總和

SELECT name 
    , house_number 
    , address 
    , SUM(gtax) as gtax 
    , SUM(htax) as htax 
    , SUM(LTAX) LTAX 
FROM (SELECT c.consumer_name as Name 
      , c.house_number 
      , c.address,h.subincome 
      , h.financial_year 
      , CASE WHEN h.subincome = 'Garbage tax' THEN f.garbage_tax - sum(h.rupees)END as gtax 
      , CASE WHEN h.subincome = 'House tax' THEN f.house_tax - sum(h.rupees) END as htax 
      , CASE WHEN h.subincome = 'Light tax' THEN f.light_tax - sum(h.rupees) END as LTAX 
     FROM house_details h 
      INNER JOIN financial_year f ON h.financial_year = f.year AND h.house_id = f.house_number 
      INNER JOIN consumer_details c ON h.house_id = c.house_number AND h.financial_year != '2017-2018' 
     GROUP BY h.subincome, h.financial_year) as main 
GROUP BY house_number

那麼結果是： Screenshot of result

來源

2017-12-18 10:12:29

通過使用mysql的組總和

回答

相關問題