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這是文件上傳的基本功能。 我需要它返回一個包含所有圖像名稱的字符串,並且如果沒有要上傳的圖像返回FALSE。我怎樣才能做到這一點?PHP,Codeigniter 2.1 - 多文件上傳和數組返回
function img_upload($folder) {
$this->path = './public/img/' . $folder;
$imgs = array();
$g = true;
$config = array(
'allowed_types' => 'jpg|jpeg|png|gif',
'upload_path' => $this->path
);
$CI = &get_instance();
$CI->load->library('upload', $config);
foreach ($_FILES as $key => $value) {
if (!$CI->upload->do_upload($key)) {
return FALSE;
} else {
$q = $CI->upload->data();
$config['image_library'] = 'gd2';
$config['source_image'] = $this->path . '/' . $q['file_name'];
$config['new_image'] = $this->path . '/thumbs';
$config['create_thumb'] = FALSE;
$config['maintain_ratio'] = TRUE;
$config['width'] = 128;
$config['height'] = 128;
$CI->load->library('image_lib', $config);
$CI->image_lib->resize();
echo $q['file_name'];
$imgs = array_push($imgs, $q['file_name']);
}
}
}
這是它。謝謝你的幫助:) – Sasha
@Sasha你的歡迎..... :) –