我想要做的是壓縮生成的csv文件。直到涉及到此代碼時,文件纔會生成而不會出現問題。因此,代碼拋出這裏zos.close()
異常的代碼使用Java壓縮csv文件會拋出一個「至少有一個ZipEntry」
try {
FileOutputStream fos = new FileOutputStream(file.getPath());
ZipOutputStream zos = new ZipOutputStream(fos);
FileInputStream in = new FileInputStream(file.getPath());
String fullCSVFileName = file.getName();
String fullFileName = fullCSVFileName.substring(0, fullCSVFileName.length()-3);
String fullZipFileName = fullFileName + "zip";
ZipEntry ze= new ZipEntry(fullZipFileName);
if(ze != null) zos.putNextEntry(ze);
fos = new FileOutputStream("C:\\sourceLocation\\"+fullZipFileName);
zos = new ZipOutputStream(fos);
byte[] buffer = new byte[1024];
int len;// = in.read(buffer);
while ((len = in.read(buffer)) > 0) {
Logger.debug("in Loop, len = " + len);
zos.write(buffer, 0, len);
}
in.close();
zos.closeEntry();
zos.close();
Logger.debug("Zipping complete!");
} catch(IOException ex) {
Logger.error(ex);
}
更正後的代碼
try{
String fullCSVFileName = file.getName();
String fullFileName = fullCSVFileName.substring(0, fullCSVFileName.length()-3);
String fullZipFileName = fullFileName + "zip";
FileOutputStream fos = new FileOutputStream("C:\\sourceLocation\\"+fullZipFileName);
ZipOutputStream zos = new ZipOutputStream(fos);
FileInputStream in = new FileInputStream(file.getPath());
ZipEntry ze= new ZipEntry(fullZipFileName);
if(ze != null){
zos.putNextEntry(ze);
}
byte[] buffer = new byte[1024];
int len;
while ((len = in.read(buffer)) > 0) {
zos.write(buffer, 0, len);
}
in.close();
zos.closeEntry();
zos.close();
Logger.debug("Zipping complete!");
}catch(IOException ex){
Logger.error(ex);
}
你可以把你的堆棧跟蹤。 – commit 2013-03-22 15:55:41
與'糾正的代碼'我得到一個zip文件那是在antoher zip文件中,它是'相同的名稱,它是'損壞或未知格式' – bouncingHippo 2013-03-22 16:13:11