調用未定義的方法mysqli_stmt :: bindParam（）

Question

正如標題所暗示的，我嘗試過不同的設置，還有其他一些問題。

$conn = new mysqli("localhost","root","root","site_db"); 

foreach($webdesigns as $designer){ 

    $whmcs_id = $designer['id']; 
    $email = $designer['email']; 
    $portfolio = json_encode($designer['designs'],JSON_FORCE_OBJECT); 

    $stmt = $conn->prepare("INSERT INTO partners (whmcs_id,email,portfolio) VALUES (?, ? , ?)"); 

    $stmt->bindParam(1, $whmcs_id); 
    $stmt->bindParam(2, $email); 
    $stmt->bindParam(3, $portfolio); 
    echo $stmt->execute(); 

} 

Answer 1

與mysqli的工作時，這是bind_param。
使用PDO時，它是bindParam。
使用MySQLi bind_param，你必須設置變量類型，1,2,3不是變量類型。
檢查這裏的變量類型：http://php.net/manual/en/mysqli-stmt.bind-param.php#refsect1-mysqli-stmt.bind-param-parameters

$conn = new mysqli("localhost","root","root","site_db"); 

foreach($webdesigns as $designer){ 

    $whmcs_id = $designer['id']; 
    $email = $designer['email']; 
    $portfolio = json_encode($designer['designs'],JSON_FORCE_OBJECT); 

    if($stmt = $conn->prepare("INSERT INTO partners (whmcs_id,email,portfolio) VALUES (?, ? , ?)")){ 

     $stmt->bind_param("iss", $whmcs_id,$email,$portfolio); 

     if(!$stmt->execute()){ 
      print_r("Error : $conn->error"); 
     } 
    } else{ 
     print_r("Error preparing: $conn->error"); 
    } 
}