爲什麼pyuv.pipe.start_read（...）在pyuv.process.spawn上導致Segementation錯誤？

Question

運行此代碼pyuv產卵一個過程，捕獲其輸出和錯誤：

#!/usr/bin/env python3 
# -*- coding: utf-8 -*- 

import pyuv 


def on_read(pipe, data, error): 
    print('data: ' + str(data)) 


def on_exit(process, exit_status, term_signal): 
    print('Process Terminated - exit code: ' + str(exit_status)) 


def start(): 

    stdin_pipe = pyuv.Pipe(pyuv.Loop.default_loop()) 
    stdout_pipe = pyuv.Pipe(pyuv.Loop.default_loop()) 
    stderr_pipe = pyuv.Pipe(pyuv.Loop.default_loop()) 

    stdout_pipe.start_read(on_read) 
    stderr_pipe.start_read(on_read) 

    stdio = [pyuv.StdIO(stream=stdin_pipe, flags=pyuv.UV_CREATE_PIPE | pyuv.UV_READABLE_PIPE), 
      pyuv.StdIO(stream=stdout_pipe, flags=pyuv.UV_CREATE_PIPE | pyuv.UV_WRITABLE_PIPE), 
      pyuv.StdIO(stream=stderr_pipe, flags=pyuv.UV_CREATE_PIPE | pyuv.UV_WRITABLE_PIPE)] 

    process = pyuv.Process(pyuv.Loop.default_loop()) 
    process.spawn(loop=pyuv.Loop.default_loop(), 
      args=['/usr/bin/wget', 'http://www.google.com'], 
      exit_callback=on_exit, 
      stdio=stdio) 

    pyuv.Loop.default_loop().run() 


if __name__ == '__main__': 
    start() 

產生一個Segmentation fault (core dumped)

談到了「start_read（）調用的管道實例的作品，但不給我是stdout和stderr。

我缺少什麼？

這是不是正確的方式來捕獲pyuv派生進程的標準輸出和標準錯誤？

Answer 1

哦，我的... Pipe.start_read()回調後Process.spawn()做到了。

process = pyuv.Process(pyuv.Loop.default_loop()) 
process.spawn(loop=pyuv.Loop.default_loop(), 
     args=['/usr/bin/wget', 'http://www.google.com'], 
     exit_callback=on_exit, 
     stdio=stdio) 

stdout_pipe.start_read(on_read) 
stderr_pipe.start_read(on_read) 

pyuv.Loop.default_loop().run() 

（面掌）