def python錯誤重複

-1

雖然我輸入了一個數值，但它仍然給我一個錯誤。我不知道這是爲什麼發生..幫助某人？def python錯誤重複

def is_string(s): 
    rate = input(s) 
    try: 
     str.isalpha(rate) 
     print('There was an error. Please try again. Make sure you use numerical values and alpabetical. ') 
     return is_string(s) #ask for input again 
    except: 
     return rate 
ExRate = is_string('Please enter the exchange rate in the order of, 1 '+Currency1+' = '+Currency2) 

def is_string2(msg): 
    amount = input(msg) 
    try: 
     str.isalpha(amount) 
     print('There was an error. Please try again. Make sure you use numerical values. ') 
     return is_string2(msg) #ask for input again 
    except: 
     return amount 
Amount = is_string2('Please enter the amount you would like to convert:')

來源

2013-03-23 ConfusedChild24

你在這裏做什麼？ – Eric 2013-03-23 22:53:18

閱讀['isalpha（）']（http://docs.python.org/2/library/stdtypes.html#str.isalpha）的文檔，您可能會發現錯誤。 – millimoose 2013-03-23 22:54:05

你的'try'子句的哪一部分是你期望拋出一個錯誤？打印「出現錯誤」不足以從「try」語句中斷開。 – Eric 2013-03-23 22:54:28

您正在尋找這樣的事情？

def get_int(prompt, error_msg): 
    while True: 
     try: 
      return int(input(prompt)) 
     except ValueError: 
      print(error_msg) 


rate = get_int(
    'Please enter the exchange rate in the order of, 1 {} = {}' 
     .format(Currency1, Currency2), 
    error_msg="Rate must be an integer") 
amount = get_int(
    'Please enter the amount you would like to convert:', 
    error_msg="Amount must be an integer")

來源

2013-03-23 22:57:50 Eric

謝謝一堆！這實際上工作！：D – ConfusedChild24 2013-03-23 23:03:27

，我不知道你爲什麼使用異常時，你應該只使用if語句：

def is_string(s): 
    rate = input(s) 
    if str.isalpha(rate): 
     print('There was an error. Please try again. Make sure you use numerical values and alpabetical. ') 
     return is_string(s) #ask for input again 
    else: 
     return rate 
ExRate = is_string('Please enter the exchange rate in the order of, 1 '+Currency1+' = '+Currency2) 

def is_string2(msg): 
    amount = input(msg) 
    if str.isalpha(amount): 
     print('There was an error. Please try again. Make sure you use numerical values. ') 
     return is_string2(msg) #ask for input again 
    else: 
     return amount 
Amount = is_string2('Please enter the amount you would like to convert:')

來源

2013-03-23 22:54:36 Xymostech

我試過如果語句，但它並沒有爲我的代碼作爲一個整體，因爲我試圖創建貨幣轉換器。謝謝。 – ConfusedChild24 2013-03-23 22:57:45

你不應該使用try語句，我不認爲你應該使用isalpha（）。 isnumeric（）測試數字有效性。 isalpha（）將爲「％＃ - @」之類的字符串返回false。

while True: 
    s = input("Enter amount: ") 
    if s.isnumeric(): 
     break 
    print("There was a problem. Enter a number.")

來源

2013-03-23 23:04:11 DXsmiley

** - 1 *單音圓括號 – Eric 2013-03-23 23:26:29

固定。現在代碼更加pythonic。 – DXsmiley 2013-03-24 00:14:31

def python錯誤重複

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