Boost屬性樹：刪除節點

如何從boost xml屬性樹中刪除節點？Boost屬性樹：刪除節點

我有一個這樣的文件：

<folders> 
    <folder>some/folder</folder> 
    <folder>some/folder</folder> 
    <folder>some/folder</folder> 
</folders>

我知道如何itereate和打印所有文件夾，但如何將我刪除的項目之一，並保存XML回來？

來源

2012-06-15 Rasmus Styrk

嗯，我就是這麼做的：

void Backups::removeGeneric(const std::string key, const std::string value) 
{ 
    boost::property_tree::ptree pt; 
    boost::property_tree::xml_parser::read_xml(Backups::getBackupFile(), pt); 

    bool remove = true; 

    try { 
     pt.get_child(key); 
    } 
    catch(boost::exception &ex) 
    { 
     std::cout << "There is nothing to remove." << std::endl; 
     remove = false; 
    } 

    if(remove) 
    { 
     bool exists = false; 

     boost::property_tree::ptree newPt; 

     BOOST_FOREACH(boost::property_tree::ptree::value_type &v, pt.get_child(key)) 
     { 
      if(v.second.data() != value) 
       newPt.add("scheme", v.second.data()); 

      if(v.second.data() == value) 
       exists = true; 
     } 

     if(exists) 
     { 
      pt.put_child(key, newPt); 
      boost::property_tree::xml_parser::write_xml(Backups::getBackupFile(), pt); 

      std::cout << value << " was removed." << std::endl; 
     } 
     else 
      std::cout << value << " is not added." << std::endl; 
    } 
}

來源

2012-06-15 10:59:23

不要使用流量控制例外。 – CaffeineAddict

void Backups::removeGeneric(const std::string key, const std::string value) 
{ 
    typedef boost::property_tree::ptree Tree; 

    Tree pt; 
    boost::property_tree::xml_parser::read_xml(Backups::getBackupFile(), pt); 

    std::pair< Tree::assoc_iterator, Tree::assoc_iterator> range = pt.equal_range(key); 
    if(range.first == pt.not_found()) 
    { 
     std::cout << "There is nothing to remove." << std::endl; 
    } 
    else 
    { 
     bool removed = false; 

     do 
     { 
      if(assoc_i->second.data() == value) { 
       Tree::iterator i = pt.to_iterator(assoc_i); 
       pt.erase(i); 
       removed = true; 
       // not sure if this is completely necessary - trying 
       // to guard against invalidating the iterator 
       // via erase - if removed, remember to ++i! 
       range = pt.equal_range(key); 
       i = range.first; 
      } 
      else 
       ++i; 
     } while(i != pt.not_found()); 

     if(removed) 
     { 
             boost::property_tree::xml_parser::write_xml(Backups::getBackupFile(), pt); 
      std::cout << value << " was removed." << std::endl; 
     } 
     else 
      std::cout << value << " is not added." << std::endl; 
    } 
}

來源

2012-10-25 04:52:24 sje397

我可能會嘗試：

boost::property_tree::ptree pt; 

pt.erase(key);

來源

2013-04-01 14:43:25 yosoy89

這將刪除第一個鍵，而不是特定的鍵 - 如果您的子樹包含多個具有相同名稱的鍵，則這是一個問題。 –

// Recursively erase nodes 
    void prune_nodes(ptree& Prop_tree, const char* Node_name) 
    { 
     ptree::iterator Root = Prop_tree.begin(); // Node iterator 
     ptree::iterator End = Prop_tree.end(); // Stop sentinel 
     // Loop through current 'Root-Level' 
     for(Root; Root != End; Root++) 
     { 
      Root->second.erase(Node_name); // Erase nodes in current 'Root-Level' sub-tree 
      prune_nodes(Root->second, Node_name); // Recurse using current sub-tree as next call's ptree 
     } 
    }

來源

2017-10-03 05:29:35

Boost屬性樹：刪除節點

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