Question

require_once($_SERVER["DOCUMENT_ROOT"] . 'config.php'); 

class stuff{ 

    public $dhb; 

    public function __construct(){ 
     $dbh = new PDO('mysql:host=' . $database['host'] . ';dbname=' . $database['dbname'] . '', $database['user'], $database['password']); 
    } 
} 

訪問陣列的配置文件在上面的例子中我得到這個錯誤：

Notice: Undefined variable: database in C:\wamp\www\career\inc\controller.php on line 11

？我怎樣才能訪問陣列我有config.php？它包含$database陣列。

Answer 1

更好的是注入的信息：

class stuff{ 

    public $dhb; 

    public function __construct($dbh){ 
     $this->dbh = $dbh; 
    } 
} 

require_once($_SERVER["DOCUMENT_ROOT"] . 'config.php'); 
$dbh = new PDO('mysql:host=' . $database['host'] . ';dbname=' . $database['dbname'] . '', $database['user'], $database['password']); 
$stuff = new stuff($dbh); // really hope this is a fake name 

Answer 2

什麼PeeHaa說看臺：

class stuff{ 

    public $dhb; 

    public function __construct($database){ 
     $dbh = new PDO('mysql:host=' . $database['host'] . ';dbname=' . $database['dbname'] . '', $database['user'], $database['password']); 
    } 
} 

require_once($_SERVER["DOCUMENT_ROOT"] . 'config.php'); 
$stuff = new stuff($database); // really hope this is a fake name 

甚至更​​快只需直接通過數據庫實例。另一種方法是使用singleton類作爲配置選項。

如果你還想做你的方式，我想$數據庫是全球性的，所以你的構造應該是：

public function __construct(){ 
     global $database; 
     $dbh = new PDO('mysql:host=' . $database['host'] . ';dbname=' . $database['dbname'] . '', $database['user'], $database['password']); 
    }