PHP的MySQL更新和插入不工作

對專業人士抱歉，我知道你得到這個很多，但我真的不知道這一點。我已經嘗試過，並嘗試過，但最近似乎我無法獲得任何服務器代碼工作。即使它在過去使用相同的代碼工作。PHP的MySQL更新和插入不工作

這是不會更新頁面：

<html> 

<head> 
<title>Gus' Private Site</title> 
<script language="javascript" src="eraseIt.js"></script> 
<script type="text/javascript"> 
function CheckInfo() 
{ 
var x=document.getElementById("user").value; 
var y=document.getElementById("pass").value; 
if (x<="" || y<="") 
    { 
    document.getElementById("txt1").innerHTML="Form not complete."; 
    } 
else if (x>"" && y>"") 
    { 
    document.getElementById("txt1").innerHTML=""; 
    document.getElementById("b1").type="submit"; 
    document.getElementById("b1").click(); 
    } 
} 
</script> 

</head> 

<body onload="eraseText()"> 



<h3>Welcome to my private website for friends and family. <br> 

It is finally up and running.</h3> 


<form name="yourInfo" target="_self" action="index.php" method="$_POST"> 
<div id="txt1"></div><br> 


Sign in <br> 

Username: <input id="user" type="text" name="uName" onkeydown="if (event.keyCode == 13) document.getElementById('b1').click()"><br> <!-- uName: userName --> 

Password: <input id="pass" type="password" name="pWord" onkeydown="if (event.keyCode == 13) document.getElementById('b1').click()"> 

<input id="b1" type="button" value="Login" onclick="CheckInfo()"> 

</form> <br> 

<?php 
$con = mysql_connect("localhost","root","panda31193"); 
if (!$con) 
    { 
    die('Could not connect: ' . mysql_error()); 
    } 

error_reporting(0); 

mysql_select_db("my_private_site", $con); 

$UaP1 = mysql_query("SELECT * FROM signinfo WHERE FirstName='Augustus'"); 
$UaP2 = mysql_query("SELECT * FROM signinfo WHERE FirstName='Bianca'"); 

$loginfo1 = mysql_query("SELECT * FROM loginfo WHERE FirstName='Augustus'"); 

$user = $_REQUEST["uName"]; 
$pass = $_REQUEST["pWord"]; 

$true = "true"; 
$false = "false"; 

$log1 = mysql_fetch_array($loginfo1); //Augustus 

$row1 = mysql_fetch_array($UaP1); //Augustus 
$row2 = mysql_fetch_array($UaP2); //Bianca 

if ($user==$row1['Username'] && $pass==$row1['Password']) //Augustus 
    { 
    mysql_query("UPDATE loginfo SET On='$true' WHERE FirstName='Augustus'"); 
    echo "<script type=\"text/javascript\">document.location.href=\"main_1.php\";</script>"; 
    } 
else if ($user==$row2['Username'] && $pass==$row2['Password']) //Bianca 
    { 
    echo "<script type=\"text/javascript\">document.location.href=\"main_2.php\";</script>"; 
    } 
else 
    { 
    null; 
    } 

mysql_close($con); 
?> 


</body> 

</html>

，這是網頁，不會讓我INSERT：

<html> 
<head> 
<script type="text/javascript"> 
function toAlex() 
{ 
    document.getElementById("T1").value="Alex"; 
} 
function toGus() 
{ 
    document.getElementById("T1").value="Gus"; 
} 
function fromAlex() 
{ 
    document.getElementById("T2").value="Alex"; 
} 
function fromGus() 
{ 
    document.getElementById("T2").value="Gus"; 
} 
function sendMessage() 
{ 
var x=document.getElementById("T1").value; 
var y=document.getElementById("T2").value; 
var z=document.getElementById("Message").value; 
if (x>"" && y>"" && z>"") 
    { 
    document.getElementById("B1").type="submit"; 
    document.getElementById("B1").click(); 
    } 
else 
    { 
    document.getElementById("B1").type="button"; 
    document.getElementById("txt1").innerHTML="Form not complete."; 
    null; 
    } 
} 
</script> 
</head> 

<body> 

<div style="position:absolute; top:26px; left:5px">To: </div> <div style="position:absolute; top:26px; left:300px" id="txt1"></div> 
<div style="position:absolute; top:71px; left:5px">From: </div> <div style="position:absolute; top:71px; left:300px" id="txt2"></div> 
<div style="position:absolute; top:121px; left:5px">Message: </div> <div style="position:absolute; top:500px; left:300px" id="txt2"></div> 
<form target="frame" method="_$POST" action="sendMessage.php"> 
<input style="position:absolute; top:25px; left:72px; width:50px" type="text" id="T1" name="T1" readonly="readonly"> 
<select style="position:absolute; top:26px; left:140px"> 
<option value="Select Contact">Select Contact</option> 
<option onclick="toAlex()" value="Alex">Alex</option> 
<option onclick="toGus()" value="Gus">Gus</option> 
</select> 
<br> 
<input style="position:absolute; top:70px; left:72px; width:50px" type="text" id="T2" name="T2" readonly="readonly"> 
<select style="position:absolute; top:71px; left:140px" id="T2" name="T2"> 
<option value="Select Contact">Select Contact</option> 
<option onclick="fromAlex()" value="Alex">Alex</option> 
<option onclick="fromGus()" value="Gus">Gus</option> 
</select> <br> <br> 
<textarea style="position:absolute; top:120px; left:72px; width:400px; height:280px" id="Message" name="Message"></textarea> 
<input style="position:absolute; top:414px; left:356px" type="button" id="B1" name="B1" value="Send Message" onclick="sendMessage()"> 
</form> 

<?php 
$con = mysql_connect("localhost","root","panda31193"); 
if (!$con) 
    { 
    die('Could not connect: ' . mysql_error()); 
    } 

error_reporting(0); 

mysql_select_db("my_private_site", $con); 

$to = $_REQUEST["T1"]; 
$from = $_REQUEST["T2"]; 
$message = $_REQUEST["Message"]; 

mysql_query("INSERT INTO other (To,From,Text) VALUES ('$to', '$from', '$message'"); 

mysql_close($con); 
?> 

</body> 
</html>

來源

2011-07-13 Augustus

一個小托架在查詢缺少有

mysql_query("INSERT INTO other (To,From,Text) VALUES ('$to', '$from', '$message')");

來源

2011-07-13 09:25:51 yogs

您應**總是**執行查詢後檢查錯誤。 – wonk0

嘿，我感謝你的意見，我相應地改變了代碼，但我仍然無法正常工作。 – Augustus

@ wonk0：我保留不檢查錯誤的權利。我選擇將我的小拇指放在嘴角，邪惡博士的風格，並說：「我只是假設它將全部按計劃進行，什麼？」。 – spencer7593

初看一眼：您的FORM標籤的方法是"$_POST"。它應該是"POST"

來源

2011-07-13 09:27:41

PHP的MySQL更新和插入不工作

回答

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