1
嗨,我使用這個class.upload.php爲我的項目,我必須說這是非常有益的。 但是我堅持這個錯誤class.upload.php獲取錯誤
沒有正確上傳的源文件。無法在過程 攜帶
任何人都可以指導我如何解決issue.Thanks 這裏就是我認爲錯誤lies..thanks
<?php
require_once('class.upload.php');
if((isset($_POST['step']))&&($_POST['step']=='process')){
$pictime = strtotime(date('Y-m-d H:i:s'));
$pic = "picture";
$id = $_POST['id'];
$category = $_POST['category'];
$username = $_POST['username'];
$path = $_SERVER['DOCUMENT_ROOT'].$_POST['tempfile'];
//connect to the server
$conn = mysql_connect('localhost','root','');
if(!$conn)
{
echo "Could not connect to the server";
}
//connect to the database
$db = mysql_select_db("enzeon_db" , $conn);
if(!$db)
{
echo "Could not connect to the database";
}
//query the database to get the imagepath and the thumbpath
$query = "SELECT * FROM machine_db WHERE id = '$id' and m_category = '$category' and username = '$username'";
$result = mysql_query($query) or die("Some error occured" . mysql_error());
$num = mysql_num_rows($result);
if($num == 1)
{
$row = mysql_fetch_array($result);
$imagepath = $row['m_imagepath'];
$imagethumb = $row['m_thumb_path'];
}
$handle = new Upload($_SERVER['DOCUMENT_ROOT'].$_POST['tempfile']);
if ($handle->uploaded) {
$handle->file_src_name_body = $pic; // hard name
$handle->file_new_name_body = 'enzeon_'.$pictime;
$handle->file_overwrite = false;
$handle->file_auto_rename = false;
$handle->image_resize = true;
$handle->file_src_pathname = true;
$handle->image_x = 200; //size of final picture
$handle->image_y = 200; //size of final picture
$handle->jcrop = true;
$handle->rect_w = $_POST['w'];
$handle->rect_h = $_POST['h'];
$handle->posX = $_POST['x'];
$handle->posY = $_POST['y'];
$handle->jpeg_quality = 100;
$handle->Process($_SERVER['DOCUMENT_ROOT'].'/LoginSystem/upload_pic/');
//thumb-50
$handle->file_src_name_body = $pic; // hard name
$handle->file_new_name_body = 'idrish_'.$pictime;
$handle->file_overwrite = false;
$handle->file_auto_rename = false;
$handle->image_resize = true;
$handle->image_x = 100;
$handle->image_y = 100; //size of picture
$handle->jcrop = true;
$handle->rect_w = $_POST['w'];
$handle->rect_h = $_POST['h'];
$handle->posX = $_POST['x'];
$handle->posY = $_POST['y'];
$handle->jpeg_quality = 100;
$handle->Process($_SERVER['DOCUMENT_ROOT'].'/LoginSystem/upload_pic/');
if($handle->processed)
{
echo "gimme some sunshine";
}
else
{
echo 'error' . $handle->error;
}
$handle->clean();
}
else {
echo "here" . $handle->error;
}
}
echo "yes";
//header("location:".$_SERVER["PHP_SELF"]);
?>
只要'$ handle =新上傳($ _ FILES ['tempfile']);' – VolkerK 2010-01-09 13:14:13
@antpaw感謝您的回覆。但我從另一個文件調用tempfile路徑,所以$ _POST我認爲是正確的。另外print_r($ _ FILES)給出一個空數組。我也嘗試把echo $ handle-> log;在我的代碼,並得到了以下輸出,錯誤「沒有正確的上傳的源文件。不能進行一個過程」你能建議別的什麼......這讓我瘋狂... – noobcode 2010-01-09 13:57:40
也許你的表單標記缺失enctype = 「多部分/格式數據」 – antpaw 2010-01-09 14:42:27