2015-09-17 23 views
0
<?php 

$next_month = strtotime("+1 month"); 

// 
$next_month_formatted = date("n", $next_month); 

$link = ""; 

if(! empty($next_month_formatted)) 

    switch($next_month_formatted % 5) 
    { 
     case '10': 
      $link = "https://rightsignature.com/forms/10-1-15-MCDONALDS-e13aff/token/da0d4ec67cf"; 
     break; 
     case '11': 
      $link = "https://rightsignature.com/forms/11-1-15-MCDONALDS-a0a0ec/token/8232d7c2265"; 
     break; 
     case '12': 
      $link = "https://rightsignature.com/forms/121-15-MCDONALDS--89d5a0/token/84b88a8c248"; 
     break; 
     case '1': 
      $link = "https://rightsignature.com/forms/1-1-16-MCDONALDS--fa49d9/token/79dd025e3f1q"; 
     break; 
     case '2': 
      $link = "https://rightsignature.com/forms/2-1-16-MCDONALDS--022aff/token/4bc0a37cf49"; 
     break; 
     case '3': 
      $link = "https://rightsignature.com/forms/3-1-16-MCDONALDS--d1313d/token/47b351070c1"; 
     break; 
     case '4': 
      $link = "https://rightsignature.com/forms/4-1-16-MCDONALDS--0cf9d2/token/bb31f6bb11e"; 
     break; 
     case '5': 
      $link = "https://rightsignature.com/forms/5-1-16-MCDONALDS--37e75d/token/d1b044125f2"; 
     break; 
     default: 
      $link = "#"; 
    } 
    echo $next_month_formatted(10); 
?> 

我想獲得返回值,但我有一個假功能。我有點新,所以我不能完全描述它是什麼。我正在根據數據範圍更改日期。根據數據範圍更改鏈接。基本錯誤我找不到,我試圖回聲情況10

我試圖迴應當前月份。我想,以反映10月的鏈接是區分10

+0

'switch($ next_month_formatted%5)' - 你在你的月份使用mod;你確定這正是你想要做的嗎? – andrewsi

+0

https://www.codecademy.com/tracks/php –

+0

那我應該怎麼做呢? – Vincent

回答

0

開關後,你迴音此:

echo $next_month_formatted(10); 

你不應該回聲$鏈接呢?

echo $link; 
+0

是的,我確實已經準備好了,但是在那個時候這會有幫助。謝謝! :) – Vincent

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