0
<?php
$next_month = strtotime("+1 month");
//
$next_month_formatted = date("n", $next_month);
$link = "";
if(! empty($next_month_formatted))
switch($next_month_formatted % 5)
{
case '10':
$link = "https://rightsignature.com/forms/10-1-15-MCDONALDS-e13aff/token/da0d4ec67cf";
break;
case '11':
$link = "https://rightsignature.com/forms/11-1-15-MCDONALDS-a0a0ec/token/8232d7c2265";
break;
case '12':
$link = "https://rightsignature.com/forms/121-15-MCDONALDS--89d5a0/token/84b88a8c248";
break;
case '1':
$link = "https://rightsignature.com/forms/1-1-16-MCDONALDS--fa49d9/token/79dd025e3f1q";
break;
case '2':
$link = "https://rightsignature.com/forms/2-1-16-MCDONALDS--022aff/token/4bc0a37cf49";
break;
case '3':
$link = "https://rightsignature.com/forms/3-1-16-MCDONALDS--d1313d/token/47b351070c1";
break;
case '4':
$link = "https://rightsignature.com/forms/4-1-16-MCDONALDS--0cf9d2/token/bb31f6bb11e";
break;
case '5':
$link = "https://rightsignature.com/forms/5-1-16-MCDONALDS--37e75d/token/d1b044125f2";
break;
default:
$link = "#";
}
echo $next_month_formatted(10);
?>
我想獲得返回值,但我有一個假功能。我有點新,所以我不能完全描述它是什麼。我正在根據數據範圍更改日期。根據數據範圍更改鏈接。基本錯誤我找不到,我試圖回聲情況10
我試圖迴應當前月份。我想,以反映10月的鏈接是區分10
'switch($ next_month_formatted%5)' - 你在你的月份使用mod;你確定這正是你想要做的嗎? – andrewsi
https://www.codecademy.com/tracks/php –
那我應該怎麼做呢? – Vincent