我試圖通過一個PDO
連接對象從一個類到另一個。但我並不是非常成功。我只想實例化一個PDO對象。如何將數據庫連接對象從一個類傳遞到另一個類?
與dqhendricks和AWM的幫助下,我設法拿到了以下解決方案工作:
class Factory {
function createUser($id = NULL) {
return new User(Conn::get_conn(), $id);
}
function createApplication($id = NULL) {
return new User(Conn::get_conn(), $id);
}
}
class Conn {
private static $conn = NULL;
private function __construct() {}
private static function init() {
$conf = self::config();
try {
self::$conn = new PDO($conf['dsn'], $conf['user'], $conf['pass']);
}
catch (PDOException $e) {
echo $e->getMessage();
}
}
public static function get_conn() {
if (!self::$conn) { self::init(); }
return self::$conn;
}
private static function config($cfg_file = 'sl.config') {
$config = parse_ini_file('/../'.$cfg_file);
$conf = array();
$conf['user'] = $config['db_user'];
$conf['pass'] = $config['db_password'];
$conf['dsn'] = 'mysql:dbname='.$config['db_name'].';host='.$config['db_host'];
return $conf;
}
}
在我UserDAO class
,我現在可以這樣做:
class UserDAO {
private $db;
private $id;
function UserDAO (&$db, $id) {
$this->db = &$db;
$this->id = &$id;
}
public function getRows($sql)
{
$result = $this->db->query($sql);
$row = $result->fetch(PDO::FETCH_ASSOC);
return $row;
}
function getUsers($limit = 10) {
$sql ="SELECT * FROM sl_store LIMIT $limit";
return $this->getRows($sql);
}
}
//My User class
class User extends UserDAO implements iUser {}
// And to test it working:
$user1 = Factory::createUser('5');
$user2 = Factory::createApplication('7');
您無法從構造函數中返回任何想要確定新語句創建的內容。一個新的聲明總是從命名的類中創建一個對象。 – dqhendricks 2011-04-02 01:59:30