0
我一直在盡我所能去使這個腳本工作,我只是無法弄清楚我做錯了什麼。我對PHP和Javascript非常陌生,我正在嘗試修改我在互聯網上發現的腳本,以便在我的網站上獲得級聯下拉菜單。這是一個相當簡單的腳本,不幸的是它不使用AJAX,因此它需要刷新頁面,但如果Im遇到困難,我不認爲我應該繼續使用AJAX。我遇到的問題是腳本應該在頁面刷新時從菜單中選擇一個棒,但它總是會重置爲默認值SELECT ONE。它在原始腳本中工作,但我已經做了很多修改,所以我不知道爲什麼我不堅持。原來的劇本是:Cascading Drop Down頁面刷新
<?php
//***************************************
// This is downloaded from www.plus2net.com //
/// You can distribute this code with the link to www.plus2net.com ///
// Please don't remove the link to www.plus2net.com ///
// This is for your learning only not for commercial use. ///////
//The author is not responsible for any type of loss or problem or damage on using this script.//
/// You can use it at your own risk. /////
//*****************************************
$dbservertype='mysql';
$servername='localhost';
// username and password to log onto db server
$dbusername='';
$dbpassword='';
// name of database
$dbname='dd';
////////////////////////////////////////
////// DONOT EDIT BELOW /////////
///////////////////////////////////////
connecttodb($servername,$dbname,$dbusername,$dbpassword);
function connecttodb($servername,$dbname,$dbuser,$dbpassword)
{
global $link;
$link=mysql_connect ("$servername","$dbuser","$dbpassword");
if(!$link){die("Could not connect to MySQL");}
mysql_select_db("$dbname",$link) or die ("could not open db".mysql_error());
}
//////// End of connecting to database ////////
?>
<!doctype html public "-//w3c//dtd html 3.2//en">
<html>
<head>
<title>Multiple drop down list box from plus2net</title>
<SCRIPT language=JavaScript>
function reload(form)
{
var val=form.cat.options[form.cat.options.selectedIndex].value;
self.location='dd.php?cat=' + val ;
}
</script>
</head>
<body>
<?
/*
If register_global is off in your server then after reloading of the page to get the value of cat from query string we have to take special care.
To read more on register_global visit.
http://www.plus2net.com/php_tutorial/register-globals.php
*/
@$cat=$_GET['cat']; // Use this line or below line if register_global is off
if(strlen($cat) > 0 and !is_numeric($cat)){ // to check if $cat is numeric data or not.
echo "Data Error";
exit;
}
//@$cat=$HTTP_GET_VARS['cat']; // Use this line or above line if register_global is off
///////// Getting the data from Mysql table for first list box//////////
$quer2=mysql_query("SELECT DISTINCT category,cat_id FROM category order by category");
///////////// End of query for first list box////////////
/////// for second drop down list we will check if category is selected else we will display all the subcategory/////
if(isset($cat) and strlen($cat) > 0){
$quer=mysql_query("SELECT DISTINCT subcategory FROM subcategory where cat_id=$cat order by subcategory");
}else{$quer=mysql_query("SELECT DISTINCT subcategory FROM subcategory order by subcategory"); }
////////// end of query for second subcategory drop down list box ///////////////////////////
echo "<form method=post name=f1 action='dd-check.php'>";
/// Add your form processing page address to action in above line. Example action=dd-check.php////
////////// Starting of first drop downlist /////////
echo "<select name='cat' onchange=\"reload(this.form)\"><option value=''>Select one</option>";
while($noticia2 = mysql_fetch_array($quer2)) {
if($noticia2['cat_id'][email protected]$cat)
{echo "<option selected value='$noticia2[cat_id]'>$noticia2[category]</option>"."<BR>";}
else{echo "<option value='$noticia2[cat_id]'>$noticia2[category]</option>";}
}
echo "</select>";
////////////////// This will end the first drop down list ///////////
////////// Starting of second drop downlist /////////
echo "<select name='subcat'><option value=''>Select one</option>";
while($noticia = mysql_fetch_array($quer)) {
echo "<option value='$noticia[subcategory]'>$noticia[subcategory]</option>";
}
echo "</select>";
////////////////// This will end the second drop down list ///////////
//// Add your other form fields as needed here/////
echo "<input type=submit value=Submit>";
echo "</form>";
?>
<center><a href='http://www.plus2net.com'>PHP SQL HTML free tutorials and scripts</a></center>
</body>
</html>
然後我的腳本:
<?php
$dbservertype='mysql';
$servername='localhost';
$dbusername='newuser';
$dbpassword='';
$dbname='supplydb';
connecttodb($servername,$dbname,$dbusername,$dbpassword);
function connecttodb($servername,$dbname,$dbuser,$dbpassword){
global $link;
$link=mysql_connect ("$servername","$dbuser","$dbpassword");
if(!$link){die("Could not connect to MySQL");}
mysql_select_db("$dbname",$link) or die ("could not open db".mysql_error());}
?>
<!doctype html public "-//w3c//dtd html 3.2//en">
<html>
<head>
<title>Multiple drop down list box from plus2net</title>
<SCRIPT language=JavaScript>
function reload(form){
var val=form.category.options[form.category.options.selectedIndex].text;
self.location='dd.php?cat=' + val ;
}
function reload2(form)
{
var val=form.cat.options[form.cat.options.selectedIndex].text;
var val2=form.subcat.options[form.subcat.options.selectedIndex].text;
self.location='dd.php?cat=' + val + '&cat2=' + val2 ;
console.log(val2);
}
</script>
</head>
<body>
<?
////// Grab Get after page refresh
$cat=$_GET['cat'];
$command="SELECT * FROM product_group WHERE type = 1";
$quer2 = mysql_query($command);
if(isset($cat) and strlen($cat) > 1){
$num = explode(' ',$cat);
$number = $num[0];
$strLen = strlen($number);
for ($i = 0; $i < $strLen; $i++)
{$arr[] = $number{$i};}
$arr1 = $arr [0];
$arr2 = $arr [1];
$arr3 = $arr1.$arr2;
$command1="SELECT * FROM `product_group` WHERE `group` LIKE '".$arr3."%' AND type = '2'";
$quer = mysql_query($command1);
}
echo "<form method=post name=category action='dd-check.php'>";
///////////// Create First Drop Down Box
echo "<select name='category' onchange=\"reload(this.form)\"><option value=''>Select one</option>";
while($query = mysql_fetch_assoc($quer2)){
if($query['group']==$cat){
echo "<option selected value='$query[group]'>$query[group]</option>"."<BR>";}
else {echo "<option value='$query[group]'>$query[group]</option>";}
}
echo "</select>";
////////////// Create Second Drop Down Box
echo "<select name='subcat' onchange=\"reload2(this.form)\"><option value=''>Select one</option>";
while($query2 = mysql_fetch_array($quer)){
if($query2['group']==$cat2)
{echo "<option selected value='$query2[group]'>$query2[group]</option>"."<BR>";}
else {echo "<option value='$query2[group]'>$query2[group]</option>";}
}
echo "</select>";
echo "</form>";
print_r ($cat);
?>
</body>
</html>
地指出任何幫助,在我的笨蛋的錯誤是會有所幫助。提前致謝。
格式化你的代碼會很有幫助。你有第一個錯誤。 – 2011-12-26 01:31:53
對不起,我現在試着修復此問題...... – 2011-12-26 01:41:32
使用空格而不是製表符,並確保每行至少有四個空格。順便說一句,你不覺得HTML3.2有點老嗎? – 2011-12-26 01:43:10