薩姆值foreach循環PHP

Question

foreach($group as $key=>$value) 
{ 
    echo $key. " = " .$value. "<br>"; 
} 

例如：

DOC1 = 8

DOC2 = 7

doc3的= 1

我想算$值，所以結果是8 + 7 + 1 = 16.我該怎麼辦？

謝謝。

Answer 1

$sum = 0; 
foreach($group as $key=>$value) 
{ 
    $sum+= $value; 
} 
echo $sum; 

Answer 2

使用+=

$val = 0; 

foreach($arr as $var) { 
    $val += $var; 
} 

echo $val; 

Answer 3

您可以使用array_sum()。

$total = array_sum($group); 

Answer 4

$total=0; 
foreach($group as $key=>$value) 
{ 
    echo $key. " = " .$value. "<br>"; 
    $total+= $value; 
} 
echo $total; 

Answer 5

你的情況，如果你想要去的foreach循環比

$sum = 0; 
foreach($group as $key => $value) { 
    $sum += $value; 
} 
echo $sum; 

但是，如果你想要去與陣列的直接和上比看下面的解決方案：

$total = array_sum($group); 

對於只有數組的總和循環是浪費時間。

http://php.net/manual/en/function.array-sum.php

array_sum - 計算在陣列中

<?php 
$a = array(2, 4, 6, 8); 
echo "sum(a) = " . array_sum($a) . "\n"; 

$b = array("a" => 1.2, "b" => 2.3, "c" => 3.4); 
echo "sum(b) = " . array_sum($b) . "\n"; 
?> 

上面的例子值的總和將輸出：

sum(a) = 20 
sum(b) = 6.9