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我使用Dygraph來顯示圖形。我把它靜態這樣工作dygraph php動態生成數據庫中的內容
<div id="graphdiv"></div>
<script type="text/javascript">
g = new Dygraph(
// containing div
document.getElementById("graphdiv"),
// CSV
"Date,High,Low\n" +
"2015-05-07,75,40\n" +
"2015-05-08,70,50\n" +
"2015-05-09,80,60\n" +
"2015-05-10,60,40\n" +
"2015-05-11,50,30\n" +
"2015-05-12,0,0\n"
);
</script>
現在我想用PHP動態生成從數據庫中的內容。我試圖這樣做。我創建了關聯數組來從數據庫中獲取信息,然後添加PHP綁定
<?php
//CREATE SQL STATEMENT
$sql_temperatures = "SELECT * FROM tbltemperatures";
//CONNECT TO MYSQL SERVER
require('inc-conndygraph.php');
//EXECUTE SQL STATEMENT
$rs_temperatures = mysqli_query($vconndygraph, $sql_temperatures);
//CREATE AN ASSOCIATIVE ARRAY
$rs_temperatures_rows = mysqli_fetch_assoc($rs_temperatures);
?>
<!doctype html>
<html>
<head>
<!-- LINK TO THE DYGRAPH LIBRARY -->
<script type="text/javascript" src="dygraph-combined-dev.js"></script>
</head>
<body>
<!-- CONTAINER HOLDING GRAPH -->
<div id="graphdiv"></div>
<script type="text/javascript">
g = new Dygraph(
// containing div
document.getElementById("graphdiv"),
"Date,High,Low\n" +
// CSV
<?php do { ?>
"<?php echo json_encode($rs_temperatures_rows['tdate']); ?>,<?php echo json_encode($rs_temperatures_rows['thigh']); ?>,<?php echo json_encode($rs_temperatures_rows['tlow']); ?>\n"
<?php } while ($rs_temperatures_rows = mysqli_fetch_assoc($rs_temperatures)); ?>
);
</script>
從理論上講,這應該在功能正常工作,但是當我嘗試它不會顯示任何瀏覽器來查看它。我錯過了一些愚蠢的東西嗎?
我在想我可能連接不正確,它顯示只是不返回?我不擅長JavaScript和任何幫助,將不勝感激。