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總和我有以下的數據幀：計算每2列
all <- structure(list(counts = c(0L, 0L, 3L, 0L, 2L, 0L), counts = c(0L,
2L, 1L, 0L, 5L, 1L), counts = c(1L, 9L, 17L, 0L, 7L, 2L), counts = c(2L,
1L, 13L, 0L, 7L, 5L), counts = c(1L, 1L, 3L, 0L, 2L, 10L), counts = c(0L,
2L, 2L, 0L, 8L, 9L), counts = c(0L, 4L, 4L, 0L, 4L, 0L), counts = c(0L,
2L, 3L, 0L, 7L, 1L), counts = c(0L, 2L, 0L, 0L, 3L, 8L), counts = c(1L,
3L, 3L, 0L, 4L, 13L), counts = c(0L, 6L, 12L, 0L, 3L, 2L), counts = c(0L,
7L, 6L, 0L, 4L, 2L), counts = c(1L, 0L, 1L, 0L, 2L, 5L), counts = c(1L,
1L, 2L, 0L, 3L, 6L), counts = c(0L, 2L, 1L, 1L, 2L, 0L), counts = c(0L,
4L, 1L, 0L, 4L, 0L), counts = c(0L, 2L, 1L, 0L, 3L, 3L), counts = c(0L,
1L, 1L, 0L, 2L, 1L), counts = c(0L, 3L, 1L, 0L, 5L, 0L), counts = c(0L,
4L, 5L, 0L, 1L, 0L), counts = c(0L, 2L, 5L, 0L, 8L, 23L), counts = c(0L,
0L, 2L, 0L, 1L, 7L), counts = c(1L, 0L, 0L, 0L, 1L, 2L), counts = c(0L,
0L, 0L, 0L, 1L, 0L)), .Names = c("counts", "counts", "counts",
"counts", "counts", "counts", "counts", "counts", "counts", "counts",
"counts", "counts", "counts", "counts", "counts", "counts", "counts",
"counts", "counts", "counts", "counts", "counts", "counts", "counts"
), row.names = c("1/2-SBSRNA4", "A1BG", "A1BG-AS1", "A1CF", "A2LD1",
"A2M"), class = "data.frame")
在該數據幀我需要每2列在最簡單的形式這是可以做到的總和：所有[1] +所有[2]，所有[3] +所有[4]等等，然後在最後我可以再次綁定新的框架，但我現在可以通過類似聚合或應用的方式來完成。只有我還沒有成功。我現在最好的嘗試是：allfinal <-aggregate(all ,FUN = sum,by=[1:2])我知道這不是它應該如何工作，但無法弄清楚如何正確使用聚合或（s）適用於做到這一點。任何提示都表示讚賞！
作爲輸出我想有一個數據框，其中包含2列的總和每1列。 data.frame現在有24列，所以最後我需要12列。
我可能只是做'所有[C（T，F）] +所有[C（F，T）]' – jdharrison
@jdharrison這更好的作品我必須說，因爲在這裏我的數據框保持一個數據框，並在下面的答案是創建一個矩陣 –