2015-08-18 61 views
0

我做data.php在查看文件夾這樣
加載XML文件的

<script type="text/javascript" src="swfobject.js"></script> 
    <div id="flashPlayer"> 
     This text will be replaced by the flash music player. 
    </div> 
<script type="text/javascript"> 
    var so = new SWFObject("playerMultipleList.swf", "mymovie", "295", "200", "7", "#FFFFFF"); 
    so.addVariable("autoPlay","yes") 
    so.addVariable("repeat","false") 
    so.addVariable("playlistPath","playlist.xml") 
    so.write("flashPlayer"); 
</script>` 

,我的問題是,我把文件swfobject.js,playerMultipleList.swf,playlist.xml上查看文件夾當我運行時,系統無法讀取所有文件。

有什麼解決辦法?

回答

0

當您在視圖中鏈接文件源時,它不會查看視圖文件夾中的文件,而是查找系統的根目錄中的文件。所以你可以在你的系統的根目錄下創建一個文件夾(應用程序,系統文件夾或index.php所在的位置),並將文件放在那裏。那麼你可以像下面的代碼一樣寫墨水。我認爲文件夾名稱是「inc」。

<script type="text/javascript" src="inc/swfobject.js"></script> 
<div id="flashPlayer"> 
    This text will be replaced by the flash music player. 
</div> 
<script type="text/javascript"> 
    var so = new SWFObject("inc/playerMultipleList.swf", "mymovie", "295", "200", "7", "#FFFFFF"); 
    so.addVariable("autoPlay","yes") 
    so.addVariable("repeat","false") 
    so.addVariable("playlistPath","playlist.xml") 
    so.write("flashPlayer"); 
</script> 
+0

不客氣。我很高興我能幫忙:) –