AlertDialog.Builder打開另一個AlertDialog.Builder

Question

我想在另一個AlertDialog中打開一個AlertDialog，但它不工作，爲什麼它不工作的任何想法？

String items[] = {"Details","Edit","Delete"} 
AlertDialog.Builder alert = new AlertDialog.Builder(getAplicationContext()); 
alert.setTitle("Options"); 
alert.setItems(items, new OnClickListener() { 

    public void onClick(DialogInterface dialog, int item) { 
     switch(item){ 
      case 0: 
       AlertDialog.Builder alert2 = new AlertDialog.Builder(getAplicationContext()); 
       alert2.setTitle("Details"); 
       alert2.setMessage(getDetails()); 
       alert2.setNeutralButton("Close", null); 
       alert2.show(); 
      return; 

      case 1: 
       //not important for the question 
      return; 

      case 2: 
       //not important for the question 
      return; 
     } 
    } 
}); 

alert.setNegativeButton("Cancel", null); 
alert.show(); 

Answer 1

該問題可能是您用於AlertDialog的環境。嘗試在兩者中使用MyActivityName.this，用您的Activity的名稱替換MyActivityName。

因此，建設的第一個AlertDialog應該是這樣的

AlertDialog.Builder alert = new AlertDialog.Builder(MyActivityName.this);

然後

AlertDialog.Builder alert2 = new AlertDialog.Builder(MyActivityName.this);

的第二個。