Java變壓器錯誤：無法編譯樣式表

Question

我想用Java中的XSLT轉換XML。爲此，我使用javax.xml.transform包。但是，我得到例外javax.xml.transform.TransformerConfigurationException: Could not compile stylesheet。這是我正在使用的代碼：

public static String transform(String XML, String XSLTRule) throws TransformerException { 

    Source xmlInput = new StreamSource(XML); 
    Source xslInput = new StreamSource(XSLTRule); 

    TransformerFactory tFactory = TransformerFactory.newInstance(); 
    Transformer transformer = tFactory.newTransformer(xslInput); // this is the line that throws the exception 

    Result result = new StreamResult(); 
    transformer.transform(xmlInput, result); 

    return result.toString(); 
} 

請注意，我標記了引發異常的行。

當我輸入方法中，XSLTRule值是這樣的：

<xsl:stylesheet version='1.0' 
xmlns:xsl='http://www.w3.org/1999/XSL/Transform' 
xmlns:msxsl='urn:schemas-microsoft-com:xslt' 
exclude-result-prefixes='msxsl' 
xmlns:ns='http://www.ibm.com/wsla'> 
    <xsl:strip-space elements='*'/> 
    <xsl:output method='xml' indent='yes'/> 
    <xsl:template match='@* | node()'> 
     <xsl:copy> 
      <xsl:apply-templates select='@* | node()'/> 
     </xsl:copy> 
    </xsl:template> 
    <xsl:template match="/ns:SLA 
          /ns:ServiceDefinition 
           /ns:WSDLSOAPOperation 
            /ns:SLAParameter[@name='Performance']"/> 
</xsl:stylesheet> 

Answer 1

的constructor

public StreamSource(String systemId) 

從URL構造一個StreamSource的。我想你會傳遞XSLT的內容。試試這個：

File xslFile = new File("path/to/your/xslt"); 
TransformerFactory factory = TransformerFactory.newInstance(); 
Templates xsl = factory.newTemplates(new StreamSource(xslFile)); 

您還必須設置OutputStream您StreamResult將寫入：

ByteArrayOutputStream baos = new ByteArrayOutputStream(); 
Result result = new StreamResult(baos); 
transformer.transform(xmlInput, result); 
return baos.toString(); 

Answer 2

你必須從你的XSLT串contruct流，然後用它作爲流源

InputStream xslStream = new ByteArrayInputStream(XSLTRule.getBytes("UTF-8")); 
Source xslInput = new StreamSource(xslStream); 

要得到的結果爲字符串：

ByteArrayOutputStream bos = new ByteArrayOutputStream(); 
    Result result = new StreamResult(bos); 
    transformer.transform(xmlInput, result); 
    String s = new String(bos.toByteArray()); 
    System.out.println(s); 

Answer 3

要使用XSLTC，請在您的類路徑中放入xalan.jar（2.5），serializer.jar，xml-apis.jar和xercesImpl.jar。