如何獲得laravel的最後一篇文章？

Question

這裏是我的表結構：

// posts 
+----+--------------+---------+ 
| id | post_content | user_id | 
+----+--------------+---------+ 
| 1 | content1  | 65743 | 
| 2 | content2  | 24711 | 
| 3 | content3  | 45541 | -- this 
| 4 | content4  | 55743 | 
| 5 | content5  | 95441 | 
| 6 | content6  | 45541 | -- this 
| 7 | content7  | 24711 | 
| 8 | content8  | 45541 | -- this (I want to select this one, Because it is the last one) 
| 9 | content9  | 24711 | 
+----+--------------+---------+ 

正如我上面已經評論說，我想下面一行，假設$user_id = 45541

| 8 | content8  | 45541 | 

我如何能做到這一點的Laravel？

我試過到目前爲止：

$last_post = Posts::where('id', $user_id)->OrderBy('id', 'desc')->first(); 

Answer 1

請修改查詢象下面這樣：

Change it From : 

OrderBy 

To: 

orderBy 

Answer 2

你可以這樣做：

$last_post = Posts::where('id', $user_id)->orderBy('id', 'desc')->first(); 

由語法正確下訂單它是這樣的：

$last_post = Posts::whereUserId($user_id)->first(); 

Answer 3

變化這一個

$last_post = Posts::where('id', $user_id)->OrderBy('id', 'desc')->first(); 

到

$last_post = Posts::where('user_id', $user_id)->orderBy('id', 'desc')->first(); 

注：爲型號名稱，我認爲更好的使用單數。更改發佈帖子