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我正在爲一個項目(與學校無關)創建一個簡單的'暴力攻擊'。有人能告訴我哪些代碼部分是錯誤的,以獲得這些錯誤。Bruteforce攻擊項目
驗證碼:
#include <string>
using namespace std;
//Password array
std::string passwordArray;
//Lowercare character array
std::string lower = { "a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m",
"n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z" };
//Uppercase character array
std::string upper = { "A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M",
"N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z" };
//Digits array
std::string digits = { "0", "1", "2", "3", "4", "5", "6", "7", "8", "9" };
private void setupCharArray()
{
if (ckhLower.Checked)
{
characterArray.AddRange(lower);
}
if (chkUpper.Checked)
{
characterArray.AddRange(upper);
}
if (chkDigits.Checked)
{
characterArray.AddRange(digits);
}
}
private void backgroundWorker1_DoWork(object sender, DoWorkEventArgs e)
{
brute();
}
,所以我嘗試使用MinGW的
編譯這段代碼G ++ bruteforce.cpp -o bruteforce.exe
,我得到這些錯誤消息
c:\Users\Lotty Playle\Documents>g++ bruteforce.cpp -o bruteforce.exe
bruteforce.cpp:7:66: error: in C++98 'lower' must be initialized by constructor,
not by '{...}'
bruteforce.cpp:7:66: error: could not convert '{"a", "b", "c", "d", "e", "f", "g
", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w
", "x", "y", "z"}' from '<brace-enclosed initializer list>' to 'std::string {aka
std::basic_string<char>}'
bruteforce.cpp:10:66: error: in C++98 'upper' must be initialized by constructor
, not by '{...}'
bruteforce.cpp:10:66: error: could not convert '{"A", "B", "C", "D", "E", "F", "
G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q", "R", "S", "T", "U", "V", "
W", "X", "Y", "Z"}' from '<brace-enclosed initializer list>' to 'std::string {ak
a std::basic_string<char>}'
bruteforce.cpp:12:73: error: in C++98 'digits' must be initialized by constructo
r, not by '{...}'
bruteforce.cpp:12:73: error: could not convert '{"0", "1", "2", "3", "4", "5", "
6", "7", "8", "9"}' from '<brace-enclosed initializer list>' to 'std::string {ak
a std::basic_string<char>}'
bruteforce.cpp:14:1: error: expected unqualified-id before 'private'
如果有人知道我做錯了什麼,他們可以讓我看看。
長x
謝謝!我無法相信我以前沒有意識到這一點。 :) – 2013-05-11 09:17:44
但請注意,語言定義不需要實現來使用ASCII,而有些系統則不需要。 – 2013-05-11 13:02:40
@PeteBecker您是否碰巧知道bruteforce.cpp:14:1:錯誤:預計'private'之前的非限定id是什麼意思? – 2013-05-11 13:32:58