問題與替換特殊字符

林用從字符串去除特殊字符的問題。我用下面的code.But力work.Please建議我更好的邏輯問題與替換特殊字符

- (NSString *)trimmedReciString:(NSString *)stringName 
{ 
    NSCharacterSet *myCharSet = [NSCharacterSet characterSetWithCharactersInString:@"-/:;()$&@\".,?!\'[]{}#%^*+=_|~<>€£¥•."]; 
    for (int i = 0; i < [stringName length]; i++) { 
     unichar c = [stringName characterAtIndex:i]; 
     if ([myCharSet characterIsMember:c]) { 
      NSLog(@"%@",[NSString stringWithFormat:@"%c",[stringName characterAtIndex:i]]); 
      stringName = [stringName stringByReplacingOccurrencesOfString:[NSString stringWithFormat:@"%c",[stringName characterAtIndex:i]] withString:@""]; 

     } 
    } 
    return stringName; 
}

來源

2012-11-21 Priyan Haridas

NSString *s = @"$$$hgh$g%k&fg$$tw/-tg"; 
NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:@"-/:;()$&@\".,?!\'[]{}#%^*+=_|~<>€£¥•."]; 
s = [[s componentsSeparatedByCharactersInSet: doNotWant] componentsJoinedByString: @""]; 
NSLog(@"String is: %@", s);

來源

2012-11-21 07:38:21

好的一個我測試此代碼輸出字符串爲：hghgkfgtwtg +1簡單的解決方案 –

優雅而簡單，感謝namrata –

嘗試從年底開始的字符串並向後工作，而不是從前往後，因爲當前一個字符被刪除時，您可能會意外（無意）跳過字符。

來源

2012-11-21 07:05:29

嘗試......

NSString *unfilteredString = @"[email protected]#$%^&*()_+|abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890"; 
NSCharacterSet *notAllowedChars = [[NSCharacterSet characterSetWithCharactersInString:@"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890"] invertedSet]; 
NSString *resultString = [[unfilteredString componentsSeparatedByCharactersInSet:notAllowedChars] componentsJoinedByString:@""]; 
NSLog (@"Result: %@", resultString);

來源

2012-11-21 07:09:48 Murali

問題與替換特殊字符

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