我讀過幾乎所有與此相關的主題。我不知道是什麼造成的。(PHP)圖像無法顯示,因爲它包含錯誤
這是用於示出圖像
<html>
<body>
<?php
mysql_connect('localhost','root','') or die("Unable to Connect: ".mysql_error());
mysql_select_db("punjabi") or die("Unable to Select Database: ".mysql_error());
$sql = "SELECT imagename, mimetype, imagedata
FROM images WHERE ID = 1";
$result = @mysql_query($sql);
if(!$result)
{
die(mysql_error());
}
$file = mysql_fetch_array($result);
$imagename = $file['imagename'];
$mimetype = $file['mimetype'];
$imagedata = $file['imagedata'];
header("content-type: $mimetype");
echo($imagedata);
?>
代碼這是爲插入圖像
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Add Post</title>
<style type="text/css">
*
{
margin:0px;
padding:0px;
}
</style>
</head>
<body bgcolor="#333333">
<?php if(isset($_POST['submit'])):
{
if (!is_uploaded_file($_FILES['uploadfile']['tmp_name']))
{
die("$uploadfile is not an uploaded file!");
}
$uploadfile = $_FILES['uploadfile']['tmp_name'];
$uploadname = $_FILES['uploadfile']['name'];
$uploadtype = $_FILES['uploadfile']['type'];
$uploaddesc = $_POST['desc'];
$tempfile = fopen($uploadfile,'rb');
$filedata = fread($tempfile,filesize($uploadfile));
$filedata = addslashes($filedata);
$sql = "INSERT INTO images SET
imagename = '$uploadname',
mimetype = '$uploadtype',
description = '$uploaddesc',
imagedata = '$filedata'";
$ok = @mysql_query($sql);
if (!$ok) die("Database error storing file: " .mysql_error());
$sql = "Select id from images where imagename = '$uploadname'";
$result = @mysql_query($sql);
if(!$result) die(mysql_error());
if(mysql_num_rows($result)!=1) die(mysql_error());
$row = mysql_fetch_array($result);
$imageid = $row['id'];
$title = $_POST['title'];
$content = $_POST['content'];
$sql = "INSERT into posts SET
title = '$title',
content = '$content',
imageid = '$imageid'";
if([email protected]_query($sql))
{
die(mysql_error());
}
header("Location:http://localhost/punjabi/adminhome.php");
}
?>
<?php else: ?>
<div id="post">
<form action="<?php echo($_SERVER['PHP_SELF']) ?>" method="post" enctype="multipart/form-data" >
Title: <input type="text" name="title" /><br /><br /><br />
Content:<br /> <textarea cols=100 rows="40" wrap="hard" name="content" /></textarea><br /><br />
Image: <input type="file" name="uploadfile" /><br /><br />
Image Desc: <input type="text" name="desc" /><br /><br />
<input type="submit" value="Submit" name="submit" />
</form>
</div>
<?php endif; ?>
</body>
</html>
的代碼,這是表結構:
CREATE TABLE filestore (
-> ID INT NOT NULL PRIMARY KEY AUTO_INCREMENT,
-> FileName VARCHAR(255) NOT NULL,
-> MimeType VARCHAR(50) NOT NULL,
-> Description VARCHAR(255) NOT NULL,
-> FileData MEDIUMBLOB
->);
和幫助,將不勝感激!
爲什麼不使用參數化插入查詢而不是'addslashes()'?我認爲這個功能修改你的內容。 –
當您直接在瀏覽器中打開生成圖像.php腳本時,您是否看到'警告:無法修改標頭信息 - 標頭已經由...發送? –
小心直接在查詢中插入unsanitized'$ _POST'。 SQL注入是一個問題! – freshnode