通過數組有條件地迭代

Question

我想將一個數組分解爲一個數組數組。

test_ary = %w(101 This is the first label 102 This is the second label 103 This is 
the third label 104 This is the fourth label) 

result = iterate_array(test_ary) 

預期輸出：

#⇒ [ 
# "101 This is the first label", 
# "102 This is the second label", 
# "103 This is the third label", 
# "104 This is the fourth label" ] 

我寫了下面的方法：

def iterate_array(ary) 
    temp_ary = [] 
    final_ary =[] 
    idx = 0 
    temp_ary.push ary[idx] 
    idx +=1 
    done = ary.length - 1 
    while idx <= done 
     if ary[idx] =~ /\d/ 
      final_ary.push temp_ary 
      temp_ary = [] 
      temp_ary.push ary[idx] 
     else 
      temp_ary.push ary[idx] 
     end 
     idx +=1 
    end 
    final_ary.push temp_ary 
    returned_ary=final_ary.map {|nested_ary| nested_ary.join(" ")} 
    returned_ary 
end 

我認爲必須有一個更簡單，更優雅的方式。有任何想法嗎？

Answer 1

根據您的函數給出的輸出結果，使用%w(101 This is the first label 102 This is the second label 103 This is the third label 104 This is the fourth label).each { |x| puts x }或使用map我得到了相同的結果。如果您可以發佈您的預期輸出，這將有所幫助。

Answer 2

這將一次遍歷數組中的兩個元素，當右側是一個數字時「斷開」（切片）它（或者當它被寫入時，當右側不包含任何非零元素時）數字字符）。希望這可以幫助！

test_ary.slice_when { |_, r| r !~ /\D/ }.map { |w| w.join(' ') } 

Answer 3

我會用Enumerable#slice_before：

test_ary.slice_before { |w| w =~ /\d/ }.map { |ws| ws.join(" ") } 
# => ["101 This is the first label", "102 This is the second label", "103 This is the third label", "104 This is the fourth label"] 

編輯：作爲@mwp說，可以讓這個更短：

test_ary.slice_before(/\d/).map { |ws| ws.join(" ") } 
# => ["101 This is the first label", "102 This is the second label", "103 This is the third label", "104 This is the fourth label"] 

Answer 4

▶ test_ary.join(' ').split(/ (?=\d)/) 
#⇒ [ 
# [0] "101 This is the first label", 
# [1] "102 This is the second label", 
# [2] "103 This is the third label", 
# [3] "104 This is the fourth label" 
# ]