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正確的文件我有以下的代碼合併兩個音頻文件合併成一個:傳遞基於字符串輸出中
import java.io.File;
import java.io.IOException;
import java.io.SequenceInputStream;
import javax.sound.sampled.AudioFileFormat;
import javax.sound.sampled.AudioInputStream;
import javax.sound.sampled.AudioSystem;
public class WavAppender {
public static void main(String[] args) {
String wavFile1 = "D:\\wav1.wav";
String wavFile2 = "D:\\wav2.wav";
try {
AudioInputStream clip1 = AudioSystem.getAudioInputStream(new File(wavFile1));
AudioInputStream clip2 = AudioSystem.getAudioInputStream(new File(wavFile2));
AudioInputStream appendedFiles =
new AudioInputStream(
new SequenceInputStream(clip1, clip2),
clip1.getFormat(),
clip1.getFrameLength() + clip2.getFrameLength());
AudioSystem.write(appendedFiles,
AudioFileFormat.Type.WAVE,
new File("D:\\wavAppended.wav"));
} catch (Exception e) {
e.printStackTrace();
}
}
}
我將有一個字符串的格式如下[1,2,3,4, 5]。根據字符串,我需要選擇適當的wav文件。例如,如果字符串格式爲[3,4,5,6,7],則需要發送wavfile 3,wavfile4,wavfile5,wavfile6和wavfile 7.實現此目的的最佳方法是什麼?
是不是第二個例子('Map')是什麼? – MadProgrammer 2014-10-10 03:28:19