列未找到 - Sqlite Android

Question

我在這裏搜索了太多，但無法解決錯誤！

我有marjorly 2班

public class DatabaseOperation extends SQLiteOpenHelper{ 
    private static final int DATABASE_VERSION = 2; 

    public String QUERY = "CREATE TABLE " + TableData.TableInfo.TABLE_NAME +"("+ TableData.TableInfo.USER_NAME+"TEXT,"+ 
      TableData.TableInfo.USER_EMAIL+"TEXT,"+ TableData.TableInfo.USER_NUMBER+"TEXT);"; 
    public DatabaseOperation(Context context){ 
     super(context, TableData.TableInfo.DATABASES_NAME,null,DATABASE_VERSION); 
    } 
    @Override 
    public void onCreate(SQLiteDatabase db){ 
     db.execSQL(QUERY); 
    } 
    @Override 
    public void onUpgrade(SQLiteDatabase db,int oldVersion,int newVersion){ 

    } 
    public void putInfo(DatabaseOperation dop,String name,String email,String pass,String no){ 
     SQLiteDatabase sq = dop.getWritableDatabase(); 
     ContentValues cv = new ContentValues(); 
     cv.put(TableData.TableInfo.USER_NAME,name); 
     cv.put(TableData.TableInfo.USER_EMAIL,email); 
     cv.put(TableData.TableInfo.USER_NUMBER,no); 
//  cv.put(TableData.TableInfo.USER_PASS,pass); 
     cv.put(TableData.TableInfo.USER_STATE,"Available"); 
     long k = sq.insert(TableData.TableInfo.TABLE_NAME,null,cv); 
    } 

    public boolean seacrhEmail(DatabaseOperation db,String email){ 

     return true; 
    } 
} 

和

public class TableData { 

    public static abstract class TableInfo implements BaseColumns{ 
     public static final String USER_NAME = "user_name"; 
     public static final String USER_EMAIL = "user_eMail"; 
//  public static final String USER_PASS = "user_pass"; 
     public static final String USER_NUMBER = "user_phNumber"; 
     public static final String DATABASES_NAME = "user_info"; 
     public static final String TABLE_NAME = "taxi_registration"; 
     public static final String USER_STATE = "taxi_state"; 
    } 
} 

錯誤當我運行INSERT語句

06-03 21:57:26.459 3700-3700/com.example.jawad.testapplication E/SQLiteLog﹕ (1) table taxi_registration has no column named user_name 
06-03 21:57:26.475 3700-3700/com.example.jawad.testapplication E/SQLiteDatabase﹕ Error inserting user_name=bb user_eMail=bb@z.n taxi_state=Available user_phNumber=666 
    android.database.sqlite.SQLiteException: table taxi_registration has no column named user_name (code 1): , while compiling: INSERT INTO taxi_registration(user_name,user_eMail,taxi_state,user_phNumber) VALUES (?,?,?,?) 
      at android.database.sqlite.SQLiteConnection.nativePrepareStatement(Native Method) 
      at android.database.sqlite.SQLiteConnection.acquirePreparedStatement(SQLiteConnection.java:893) 
      at android.database.sqlite.SQLiteConnection.prepare(SQLiteConnection.java:504) 
      at android.database.sqlite.SQLiteSession.prepare(SQLiteSession.java:588) 
      at android.database.sqlite.SQLiteProgram.<init>(SQLiteProgram.java:58) 
      at android.database.sqlite.SQLiteStatement.<init>(SQLiteStatement.java:31) 
      at android.database.sqlite.SQLiteDatabase.insertWithOnConflict(SQLiteDatabase.java:1492) 
      at android.database.sqlite.SQLiteDatabase.insert(SQLiteDatabase.java:1364) 
      at com.example.jawad.testapplication.d.a(Unknown Source) 
      at com.example.jawad.testapplication.r.onClick(Unknown Source) 
      at android.view.View.performClick(View.java:4463) 
      at android.view.View$PerformClick.run(View.java:18770) 
      at android.os.Handler.handleCallback(Handler.java:808) 
      at android.os.Handler.dispatchMessage(Handler.java:103) 
      at android.os.Looper.loop(Looper.java:193) 
      at android.app.ActivityThread.main(ActivityThread.java:5292) 
      at java.lang.reflect.Method.invokeNative(Native Method) 
      at java.lang.reflect.Method.invoke(Method.java:515) 
      at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:824) 
      at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:640) 
      at dalvik.system.NativeStart.main(Native Method) 

我跟着this tutorial ...我不知道我錯過了什麼......

PS：我對android有點新。

Answer 1

您的SQLite創建腳本

public String QUERY = "CREATE TABLE " + TableData.TableInfo.TABLE_NAME +"("+ TableData.TableInfo.USER_NAME+" TEXT,"+ 
     TableData.TableInfo.USER_EMAIL+" TEXT,"+ TableData.TableInfo.USER_NUMBER+" TEXT);"; 

添加空格之後，你應該增加2你DATABASE_VERSION至3，以執行的sqlite的

private static final int DATABASE_VERSION = 3; 

升級方法

在升級數據庫事件中，您應該刪除表並重新創建它。

@Override 
public void onUpgrade(SQLiteDatabase db,int oldVersion,int newVersion){ 
     db.execSQL("DROP TABLE IF EXISTS " + TableData.TableInfo.TABLE_NAME); 
     db.execSQL(QUERY); 
} 

Answer 2

我相信問題很簡單。

public static final String USER_NAME = "user_name";

我相信你可以找到沒有列簡單的原因它的名字是不同的。

按照你創建表，您的用戶名欄的名字是不是

USER_NAME

但

user_nameTEXT

，因爲沒有空間名稱和列類型之間。

public String QUERY = "CREATE TABLE " + TableData.TableInfo.TABLE_NAME +"("+ TableData.TableInfo.USER_NAME+"TEXT,"+ 
     TableData.TableInfo.USER_EMAIL+"TEXT,"+ TableData.TableInfo.USER_NUMBER+"TEXT);"; 

嘗試在列類型之前添加一個空格。 像這樣：

public String QUERY = "CREATE TABLE " + TableData.TableInfo.TABLE_NAME +"("+ TableData.TableInfo.USER_NAME+" TEXT,"+ 
     TableData.TableInfo.USER_EMAIL+" TEXT,"+ TableData.TableInfo.USER_NUMBER+" TEXT);";