MySQL的左連接的SQL查詢列表中的解決方案

Question

喜我的問題左連接SQL查詢

contact_message表（1個數據）
-id
-messageid
-message
-date

列表contact_message數據

Array 
(
    [0] => Array 
     (
      [id] => 5 
      [messageid] => 1 
      [message] => A new e-mail 
      [date] => 2017-01-18 
     ) 

) 

contact_reply表（2數據）
-id
-messageid
-reply
-date
列表contact_reply數據

Array 
(
    [0] => Array 
     (
      [id] => 1 
      [messageid] => 5 
      [reply] => Thanks I save mail adress 
      [date] => 2017-01-18 
     ) 

    [1] => Array 
     (
      [id] => 1 
      [messageid] => 5 
      [reply] => Sorry What is your name ? 
      [date] => 2017-01-18 
     ) 

) 

SQL查詢

SELECT im.message,im.date,ic.reply,ic.date 
     from contact_message as im 
     left join contact_reply as ic 
     on im.id=ic.messageid 
     where im.messageid=:siral 

結果

Array 
(
    [0] => Array 
     (
      [message] => A new e-mail 
      [date] => 2017-01-18 
      [reply] => Thanks I save mail adress İSMAİL ÇİLOĞLU 
     ) 

    [1] => Array 
     (
      [message] => A new e-mail 
      [date] => 2017-01-18 
      [reply] => Sorry What is your name ? 
     ) 

) 

正常[1] INDIS消息null值，但寫的[0] INDIS [消息]值
我想結果

Array 
    (
     [0] => Array 
      (
       [message] => A new e-mail 
       [date] => 2017-01-18 
       [reply] => Thanks I save mail adress İSMAİL ÇİLOĞLU 
      ) 

     [1] => Array 
      (
       [message] =>null 
       [date] => 2017-01-18 
       [reply] => Sorry What is your name ? 
      ) 

    ) 

Answer 1

你的表結構似乎是不正確

Contact_message table (1 data) 
-id 
-messageid 
-message 
-date 

contact_reply表（2數據）

-id 
-contact_message_id // Foreign Key of table1 
-reply 
-date 

Sql查詢

SELECT im.message,im.date,ic.reply,ic.date 
    from contact_message as im 
    left join contact_reply as ic 
    on im.id=ic.contact_message_id 
    where im.messageid=:siral