boost::filesystem
庫的哪些方法可以幫助我獲取相對於另一個路徑的路徑?boost :: filesystem獲取相對路徑
我有一個路徑/home/user1/Downloads/Books
和路徑/home/user1/
。現在我想要一條路徑Downloads/Books
。
boost::filesystem
庫的哪些方法可以幫助我獲取相對於另一個路徑的路徑?boost :: filesystem獲取相對路徑
我有一個路徑/home/user1/Downloads/Books
和路徑/home/user1/
。現在我想要一條路徑Downloads/Books
。
從鏈接摘自以下尼科爾掛票發現:
template < >
path& path::append< typename path::iterator >(typename path::iterator begin, typename path::iterator end, const codecvt_type& cvt)
{
for(; begin != end ; ++begin)
*this /= *begin;
return *this;
}
// Return path when appended to a_From will resolve to same as a_To
boost::filesystem::path make_relative(boost::filesystem::path a_From, boost::filesystem::path a_To)
{
a_From = boost::filesystem::absolute(a_From); a_To = boost::filesystem::absolute(a_To);
boost::filesystem::path ret;
boost::filesystem::path::const_iterator itrFrom(a_From.begin()), itrTo(a_To.begin());
// Find common base
for(boost::filesystem::path::const_iterator toEnd(a_To.end()), fromEnd(a_From.end()) ; itrFrom != fromEnd && itrTo != toEnd && *itrFrom == *itrTo; ++itrFrom, ++itrTo);
// Navigate backwards in directory to reach previously found base
for(boost::filesystem::path::const_iterator fromEnd(a_From.end()); itrFrom != fromEnd; ++itrFrom)
{
if((*itrFrom) != ".")
ret /= "..";
}
// Now navigate down the directory branch
ret.append(itrTo, a_To.end());
return ret;
}
棒,在一個頭文件,它應該做你想做的。
樣品電話:
boost::filesystem::path a("foo/bar"), b("foo/test/korv.txt");
std::cout << make_relative(a, b).string() << std::endl;
在該示例調用中不需要限定'make_relative'。它可能是錯誤的(給定的代碼看起來不像'make_relative'在'boost :: filesystem'中),如果它是正確的,由於ADL,它是沒有必要的。 – MSalters 2013-08-26 11:22:49
不幸的是,Boost.Filesystem中不存在這樣的函數。
It has been requested,但他們似乎並不在乎。
你基本上必須手動完成。
Boost.Filesystem 1.60增加了the relative
function可以用來處理這個。
實際上,該補丁被拒絕的原因(使用附加)。 – 2012-04-16 00:55:22
@ MahmoudAl-Qudsi:我鏈接到一個功能請求。在該請求的評論中有一個補丁鏈接,但它不是請求的*部分*。 – 2012-04-16 01:09:56
你說得對。也許還有更多的評論會有幫助? :) – 2012-04-16 01:49:12
接受的答案的代碼不起作用。它應該是
namespace boost { namespace filesystem {
template <> path& path::append<path::iterator>(path::iterator begin, path::iterator end, const codecvt_type& cvt)
{
for(; begin != end ; ++begin)
*this /= *begin;
return *this;
}
// Return path when appended to a_From will resolve to same as a_To
boost::filesystem::path make_relative(boost::filesystem::path a_From, boost::filesystem::path a_To)
{
a_From = boost::filesystem::absolute(a_From); a_To = boost::filesystem::absolute(a_To);
boost::filesystem::path ret;
boost::filesystem::path::const_iterator itrFrom(a_From.begin()), itrTo(a_To.begin());
// Find common base
for(boost::filesystem::path::const_iterator toEnd(a_To.end()), fromEnd(a_From.end()) ; itrFrom != fromEnd && itrTo != toEnd && *itrFrom == *itrTo; ++itrFrom, ++itrTo);
// Navigate backwards in directory to reach previously found base
for(boost::filesystem::path::const_iterator fromEnd(a_From.end()); itrFrom != fromEnd; ++itrFrom)
{
if((*itrFrom) != ".")
ret /= "..";
}
// Now navigate down the directory branch
ret.append(itrTo, a_To.end());
return ret;
}
} } // namespace boost::filesystem
的代碼所提供的答案是相當長的,每行。假設你寫namespace fs = boost::filesystem;
那麼這段代碼可以讓你最的方式,看起來更容易讀給我聽:
static fs::path relativeTo(fs::path from, fs::path to)
{
// Start at the root path and while they are the same then do nothing then when they first
// diverge take the entire from path, swap it with '..' segments, and then append the remainder of the to path.
fs::path::const_iterator fromIter = from.begin();
fs::path::const_iterator toIter = to.begin();
// Loop through both while they are the same to find nearest common directory
while (fromIter != from.end() && toIter != to.end() && (*toIter) == (*fromIter))
{
++toIter;
++fromIter;
}
// Replace from path segments with '..' (from => nearest common directory)
fs::path finalPath;
while (fromIter != from.end())
{
finalPath /= "..";
++fromIter;
}
// Append the remainder of the to path (nearest common directory => to)
while (toIter != to.end())
{
finalPath /= *toIter;
++toIter;
}
return finalPath;
}
這工作對我來說 – 2015-10-09 14:33:05
這看起來比其他答案好多了。 – 2015-12-26 18:52:31
在boost
新版本(在1.60開始),就可以使用boost::filesystem::relative
。 (See the documentation here.)
#include <boost/filesystem.hpp>
#include <iostream>
namespace fs = boost::filesystem;
int main()
{
fs::path parentPath("/home/user1/");
fs::path childPath("/home/user1/Downloads/Books");
fs::path relativePath = fs::relative(childPath, parentPath);
std::cout << relativePath << std::endl;
}
所有其他都失敗,將兩者都轉換爲絕對字符串和子字符串。 – 2012-04-16 00:33:25
新版本的boost有一個非常簡單的**答案,提供[下面](https://stackoverflow.com/a/37715252/16287) – 2017-10-12 22:11:33