T-SQL：[列]不像[從另一個選擇的任何值]

Question

我有表shop與Email列。

另外我還有另一個表Unsubscribed與EmailPattern列。

如何才能選擇只與Email列的商店列不匹配任何EmailPattern值從Unsubscribed表？

例子：

退訂有這些記錄：

aaa 
bbb 
ccc 

我希望像結果：

select * 
from Shop 
where Email not like "%aaa%" 
    and Email not like "%bbb%" 
    and Email not like "%ccc%" 

Answer 1

Select * 
From shop 
Where not exists (
    Select 1 
    From unsubscribed 
    Where shop.email like '%' + unsubcribed.emailpattern + '%' 
) 

Answer 2

這將工作：

-- setup test tables 
CREATE TABLE #Shop (ID INT, Email VARCHAR(100)); 
CREATE TABLE #Unsubscribed (EmailPattern VARCHAR(100)); 

-- fill with example data 
INSERT #Shop VALUES (1,'test@a.com'); 
INSERT #Shop VALUES (2,'david@r.com'); 
INSERT #Shop VALUES (3,'user@r.com'); 
INSERT #Shop VALUES (4,'george@usa.com'); 
-- general phrase 
INSERT #Unsubscribed VALUES ('test'); 
-- specific email 
INSERT #Unsubscribed VALUES ('user@r.com'); 
--INSERT #Unsubscribed VALUES ('@'); -- watch out, this will match every email! 
--INSERT #Unsubscribed VALUES ('_'); -- so will this 

-- filter results: 
-- This returns rows from Table A (Shop), when they do not match anything in table B (Unsubscribed) 
SELECT 
    A.* 
FROM 
    #Shop A 
    LEFT JOIN #Unsubscribed B ON A.Email LIKE '%' + B.EmailPattern + '%' 
WHERE 
    B.EmailPattern IS NULL; 

DROP TABLE #Shop; 
DROP TABLE #Unsubscribed; 

請注意，如果某些短語或字符進入取消訂閱模式，它可能會匹配每個記錄！