iOS swift firebase auth不正確登錄

Question

我使用Firebase身份驗證設置了登錄場景。在輸入正確的細節時，場景應該通過執行「loggedIn」segue進行更改。在輸入不正確的細節時，錯誤應該打印到控制檯並且什麼都不應該發生。

我發現，儘管發現錯誤（並將其打印到控制檯），控制器仍然執行segue並移至下一個屏幕（但不會將「LOGGING IN」打印到控制檯）。發現這種行爲很奇怪，有什麼想法？

我抄我的日誌在視圖控制器下面：

import Foundation 
import Firebase 
import FBSDKCoreKit 
import FBSDKLoginKit 

class LogInViewController: UIViewController{ 
@IBOutlet weak var Email: UITextField! 
@IBOutlet weak var Password: UITextField! 

@IBAction func Login(_ sender: AnyObject) { 
    let email = self.Email.text! 
    let password = self.Password.text! 

    if (email != "" && password != ""){ 
     FIRAuth.auth()?.signIn(withEmail: email, password: password, completion: { (user, error) in 
      if(error==nil){ 
       print("LOGGING IN") 
       self.performSegue(withIdentifier: "loggedIn", sender: nil) 
      } 
      else{ 
       print("COULDNT LOG IN") 
       print(error) 
      } 
     }) 
    } 
    else{ 
     let alert = UIAlertController(title: "Error", message: "Enter email and password", preferredStyle: .alert) 
     let action = UIAlertAction(title: "OK", style: .default, handler: nil) 
     alert.addAction(action) 
     self.present(alert, animated: true, completion: nil) 
    } 
} 
} 

Storyboard

編輯

我在加入故事板ID loggedInViewControllerVC_ID到mealViewController身份檢查員。

這是我的新代碼：

import Firebase 
import FBSDKCoreKit 
import FBSDKLoginKit 

class LogInViewController: UIViewController{ 

@IBOutlet weak var Email: UITextField! 
@IBOutlet weak var Password: UITextField! 
@IBAction func Login(_ sender: AnyObject) { 
    let email = self.Email.text! 
    let password = self.Password.text! 

    if (email != "" && password != ""){ 
     FIRAuth.auth()?.signIn(withEmail: email, password: password, completion: { (user, error) in 
      if(error==nil){ 
       print("LOGGING IN") 
       let nextViewController = self.navigationController?.storyboard?.instantiateViewController(withIdentifier: "loggedInViewControllerVC_ID") as! MealViewController 
       self.navigationController?.pushViewController(nextViewController, animated: true) 
       //self.performSegue(withIdentifier: "loggedIn", sender: nil) 
      } 
      else{ 
       print("COULDNT LOG IN") 
       print(error) 
      } 
     }) 
    } 
    else{ 
     let alert = UIAlertController(title: "Error", message: "Enter email and password", preferredStyle: .alert) 
     let action = UIAlertAction(title: "OK", style: .default, handler: nil) 
     alert.addAction(action) 
     self.present(alert, animated: true, completion: nil) 
    } 
} 
} 

現在我對成功輸入登錄信息

Answer 1

如果你已經在你的故事板通過賽格瑞連接您的按鈕LoogedIn的viewController得到一個BAD_INSTRUCTION錯誤。它會延續UI。你可以做的是實例化你的viewController，然後來回延伸。

從故事板中刪除該segue。

let loggedInScene = self.navigationController?.storyboard?.instantiateViewController(withIdentifier: "loggedInViewVontrollerVC_ID") as! loggedInViewVontroller 

self.navigationController?.pushViewController(loggedInScene, animated: true) 

PS： - loggedInViewVontrollerVC_ID是你對的loggedIn的viewController

storyboardID選擇的viewController要Segue公司在故事板 - >身份監察長>故事板ID - >loggedInViewVontrollerVC_ID 。

並確保您已在第一個viewController中的導航控制器中嵌入。