無法發送郵件通過SparkPost使用Python客戶

Question

我試圖使用SparkPost SMTP API

response = spark.transmissions.send(
    recipients=['somemail@example.com'], 
    text='hi', 
    content={ 
     "template_id": "my-first-email", 
     "from":{"name": "someone", "email": "no-reply@jhuthmatbolo.com"}, 
    }, 
    subject='Subject Line', 
    substitution_data={ 
     "name": "Your Name" 
    } 
) 

按照documentation它應該工作來發送郵件，但我收到以下錯誤保存的模板。

Traceback (most recent call last): 
    File "sendmail.py", line 69, in <module> 
    sparkpost() 
    File "sendmail.py", line 65, in sparkpost 
    "name": "Rupesh" 
    File "/usr/local/lib/python2.7/dist-packages/sparkpost/transmissions.py", line 254, in send 
    results = self.request('POST', self.uri, data=json.dumps(payload)) 
    File "/usr/local/lib/python2.7/dist-packages/sparkpost/base.py", line 41, in request 
    **kwargs) 
    File "/usr/local/lib/python2.7/dist-packages/sparkpost/base.py", line 16, in request 
    raise SparkPostAPIException(response) 
sparkpost.exceptions.SparkPostAPIException: Call to https://api.sparkpost.com/api/v1/transmissions returned 422, errors: 

     required field is missing Code: 1400 Description: content.from is a required field 

PS-一切工作正常與Sparkpost提供郵差例子。

Answer 1

當您使用存儲的模板（通過設置template_id）時，您不需要設置content或subject，因爲它們已嵌入模板中。你可以讓你的電話是這樣的：

response = sp.transmissions.send(
    recipients=['you@me.com'], 
    template='my-template-id' 
) 

此外，python-sparkpost API客戶端提供的API SparkPost之上的一層所以SparkPost.transmissions.send()的參數不是1：1匹配的API。 python-sparkpost的完整文檔是available here。

Here's a relevant sample也來自Python客戶端。