jQuery，Razor，Variables，URLs ...如何使用@ Url.Action

我有一個CodesController和索引行動看起來像這樣。jQuery，Razor，Variables，URLs ...如何使用@ Url.Action

public ActionResult Index(int id, string manufacturerName)

我想要的網址看起來像http://www.domain.com/codes/[id]/[manufacturerName]但我目前使用的代碼它原來的樣子http://www.domain.com/codes/[id]?manufacturerName=[manufacturerName]

<script type="text/javascript"> 
    $(function() { 
     $('#btnNext').click(function() { 
      var _id = $('#ddlManufacturers').val(); 
      var _manufacturerName = $('#ddlManufacturers').text(); 
      var url = '@Url.Action("Index", "Codes", new { id = "_id", manufacturerName = "_manufacturerName" })' 
      .replace('_id', _id).replace('_manufacturerName', _manufacturerName.toLowerCase().trim()); 
      window.location.href = url; 
     }); 
    });

這是我怎麼現在不知道這樣做如何正確地做這樣的URL證明我想要的方式。該代碼

來源

2013-10-02 Shane LeBlanc

您將需要一個新的路徑：

routes.MapRoute(
    name: null, 
    url: "{controller}/{action}/{id}/{manufacturerName}", 
    defaults: new { 
     controller = "Home", 
     action = "Index", 
     id = UrlParameter.Optional, 
     manufacturerName = UrlParameter.Optional 
    } 
);

來源

2013-10-02 19:20:23

按我的理解，你將需要添加像

routes.MapRoute(
    name: "CodesRoute", 
    url: "{controller}/{action}/{id}/{manufacturerName}", 
    new { controller = "Codes", action = "Index", 
     manufacturerName = UrlParameter.Optional 
    } 
);

的路線後，您可以使用Html.RouteLink或Url.RouteUrl

當您使用JavaScript時Url.RouteUrl將會有用

var url = '@Url.RouteUrl("CodesRoute", new { id = "_id", manufacturerName = "_manufacturerName" })'

來源

2013-10-02 19:22:23 Satpal

jQuery，Razor，Variables，URLs ...如何使用@ Url.Action

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