從字符串正則表達式刪除字符串

Question

我有一個自動生成的字符串，如下所示：

["January","February",null,"April"] 

我需要從字符串中刪除的「空」任何比賽，即：

["January","February",null,"April"] --> ["January","February","April"] 

我怎樣才能找到除",null"之外的所有東西？

我試過"^(?!,null).*"的變體沒有成功。

Answer 1

要回答你的問題是說，你不需要正則表達式：

str = str.replace(",null", ""); 

然而，處理邊界情況太：

["January","February",null,"April"] --> ["January","February","April"] 
["January",null,null,"April"] --> ["January","April"] 
[null,"January","February","April"] --> ["January","February","April"] 
["January","February","April",null] --> ["January","February","April"] 
[null] --> [] 

你會可以更好地與正則表達式服務：

str = str.replaceAll("(?<=\\[)null,?|,null", ""); 

更換正則表達式迎合f或第一個（也可能是唯一的）職位，以及任何其他情況。

Answer 2

請仔細閱讀這一塊，我們可以使用過濾功能

var arr = [null, "January","February",null,"April", null]; 
 

 
var arr2 = arr.filter(function(x){return x !== null}) 
 

 
console.log(arr,arr2);