如何初始化字符**一個struct

Question

裏面我有一個結構

struct cmd{ 

    char **tokenized_cmd; 
    int num_params; 
} 

在某些時候我需要初始化tokenized_cmd從另一個數組傳遞值到它

如何做到這一點？

Answer 1

#include <stdio.h> 

char *arr[] = {"one", "two"}; 

struct cmd { 
    char **tokenized_cmd; 
    int num_params; 
} x = {arr, 2}; 

int main(void) 
{ 
    int i; 

    for (i = 0; i < x.num_params; i++) 
     printf("%s\n", x.tokenized_cmd[i]); 
    return 0; 
} 

或

#include <stdio.h> 

struct cmd { 
    char **tokenized_cmd; 
    int num_params; 
}; 

int main(void) 
{ 
    char *arr[] = {"one", "two"}; 
    struct cmd x = {arr, 2}; 
    int i; 

    for (i = 0; i < x.num_params; i++) 
     printf("%s\n", x.tokenized_cmd[i]); 
    return 0; 
} 

或更靈活：

#include <stdio.h> 
#include <stdlib.h> 

struct cmd { 
    char **tokenized_cmd; 
    int num_params; 
}; 

struct cmd *cmd_init(char **token, int params) 
{ 
    struct cmd *x = malloc(sizeof *x); 

    if (x == NULL) { 
     perror("malloc"); 
     exit(EXIT_FAILURE); 
    } 
    x->tokenized_cmd = token; 
    x->num_params = params; 
    return x; 
} 

int main(void) 
{ 
    char *arr[] = {"one", "two"}; 
    struct cmd *x = cmd_init(arr, 2); 
    int i; 

    for (i = 0; i < x->num_params; i++) 
     printf("%s\n", x->tokenized_cmd[i]); 
    free(x); 
    return 0; 
}