你可以用Success
屬性返回JsonResult
,要麼視圖或錯誤Message
,你可以從你的Ajax響應對象讀取的Html
:
[HttpPost]
public JsonResult AddUpdateConfigs(StorageConfigurationModel modelbind)
{
if(!allowed) {
return Json(new { Success = false, Message = "blah blah blah"}, JsonRequestBehavior.DenyGet);
}
else
{
return Json(new {Success = true, Html = RenderPartialView("cbpnlNewUpdateConfigs", model)}, JsonRequestBehavior.DenyGet);
}
}
public static class PartialViewHelper
{
public static string RenderPartialView(this Controller controller, string viewName, object model)
{
if (string.IsNullOrEmpty(viewName))
viewName = controller.ControllerContext.RouteData.GetRequiredString("action");
controller.ViewData.Model = model;
using (var sw = new StringWriter())
{
ViewEngineResult viewResult = ViewEngines.Engines.FindPartialView(controller.ControllerContext, viewName);
var viewContext = new ViewContext(controller.ControllerContext, viewResult.View, controller.ViewData, controller.TempData, sw);
viewResult.View.Render(viewContext, sw);
return sw.GetStringBuilder().ToString();
}
}
public static string RenderView(this Controller controller, string viewName, object model)
{
if (string.IsNullOrEmpty(viewName))
viewName = controller.ControllerContext.RouteData.GetRequiredString("action");
controller.ViewData.Model = model;
using (var sw = new StringWriter())
{
ViewEngineResult viewResult = ViewEngines.Engines.FindView(controller.ControllerContext, viewName, String.Empty);
var viewContext = new ViewContext(controller.ControllerContext, viewResult.View, controller.ViewData, controller.TempData, sw);
viewResult.View.Render(viewContext, sw);
return sw.GetStringBuilder().ToString();
}
}
}
與您的解決方案一樣,但是當我將數據添加到數據庫時,那麼我應該返回說它是成功的? – AAlferez
我想你有錯誤時填寫一些html容器元素與你的迴應(部分視圖)。那麼當一切正常時,你可以返回一個不同的局部視圖。 – polkduran
我這樣做了,但是我的onSuccess功能沒有觸發 – AAlferez