相同的功能，但不使用繼續和休息？

Question

你將如何重組這個代碼，所以它不使用繼續和休息？我已經嘗試過但沒有運氣。感謝

import java.util.*; 

public class q6 { 
    public static void main(String args[]) { 
     int Number; 
     Scanner sc = new Scanner(System.in); 

     while (true) // seemingly an infinite loop 
     { 
      System.out.print("Enter a positive integer "); 
      System.out.println("or 0 to exit "); 
      Number = sc.nextInt(); 
      if (Number == 0) 
       break; 
      else if (Number < 0); 
      System.out.print("Squareroot of " + Number); 
      System.out.println(" = " + Math.sqrt(Number)); 
      //continue lands here at end of current iteration 
     } 
     //break lands here 
     System.out.println("a zero was entered"); 
    } 
} 

Answer 1

import java.util.*; 

    public class q6 { 
     public static void main(String args[]) { 
     int Number; 
     Scanner sc = new Scanner(System.in); 


     System.out.print("Enter a positive integer "); 
     System.out.println("or 0 to exit "); 
     Number = sc.nextInt(); 

    while (Number>0)// looping while number >0 
    { 
     System.out.print("Squareroot of " + Number); 
     System.out.println(" = " + Math.sqrt(Number)); 
     Number = sc.nextInt(); 
    } 
    System.out.println("a zero was entered"); 
} 

Answer 2

import java.util.*; 

class q6 { 
    public static void main(String args[]) { 
    int Number; 
    Scanner sc = new Scanner(System.in); 

while (instruct() && (Number=sc.nextInt())!=0) // seemingly an infinite loop 
{ 
    if (Number < 0); 
    System.out.print("Squareroot of " + Number); 
    System.out.println(" = " + Math.sqrt(Number)); 
    //continue lands here at end of current iteration 
} 
//break lands here 
System.out.println("a zero was entered"); 
} 
static boolean instruct() 
{ 
    System.out.print("Enter a positive integer "); 
    System.out.println("or 0 to exit "); 
    return true; 
} 
}