從JSON數組檢索數據

Question

我試圖從由bit.ly API返回的JSON數組中獲得的價值

的迴應是：

{"status_code": 200, "data": {"bundle": {"og_image": null, "bundle_owner": "user", "created_ts": 1423596727, "description": "", "links": [{"updated_by": null, "title": "", "display_order": 0, "lm": 1423597992.378417, "ts": 1423597992.378417, "comments": [], "aggregate_link": "http://bit.ly/LmvF", "long_url": "http://google.com/", "link": "http://bit.ly/1AUeg5k", "preview": 1, "added_by": "rentthesun"}], "title": "Barcelona 226", "collab": [], "private": true, "inv_collab": [], "last_modified_ts": 1423597992, "bundle_link": "http://bitly.com/bundles/myuser/2", "preview": true}}, "status_txt": "OK"} 

我想「環節的價值「

我的代碼：

$.getJSON("https://api-ssl.bitly.com/v3/bundle/link_add?", { 
    "access_token": "MY_TOKEN", 
     "bundle_link": "https://bitly.com/bundles/user/2", 
     "link": raw_url, 
}, function(response) { 
     $("#link-container").show("fast"); 
     link = "<a href=\"" + response.data['bundle']['links'].link[0] + "\" target=\"_blank\">" + response['data']['bundle']['links'].link[0] + "</a>"; 
     $("#link").html(link); 
}); 

我怎樣才能縮短的鏈接？

Answer 1

link = "<a href=\"" + response.data['bundle']['links'].link[0] + "\" target=\"_blank\">" + response['data']['bundle']['links'].link[0] + "</a>"; 

我想你的意思response['data']['bundle']['links'][0].link。這將選擇第一個元素的鏈接，而您的原始代碼正在查找link數組的第一個元素。

如果你總是需要它的最後一個環節，最簡單的方法來保存鏈接陣列，並得到了它的最後一個元素：

links = response.data['bundle']['links']; 
link = "<a href=\"" + links[links.length-1].link + "\" target=\"_blank\">" + links[links.length-1].link + "</a>";