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我使用這段代碼,並在行時打印(jsonResponse [「data」]),我很快又容易地從API中收到返回。Alamofire 4.0和Swfit 3的字典
但是在第一個循環中,我有一個無限循環。我需要做這個循環,因爲我的API返回。
任何人都可以幫到我嗎?我使用相同的代碼來獲取課程資料和填充的tableview及其工作......但現在這一類的不是學校工作,我收到了我的API相同的結構:
SWIFT CODE:
func findSchools(){
let parameters: Parameters = [:]
let headers: HTTPHeaders = [
"ContentType": "application/json"
]
API.consultAPI(headers: headers, type: .get, parameters: parameters, endpoint: "schools", completionSuccess: { (response) in
if let responseValue: AnyObject = response.result.value as AnyObject? {
let jsonResponse = JSON(responseValue)
print(jsonResponse["data"])
for (_, data) in jsonResponse["data"]{
print(data)
if data["id"] != nil && data["name"] != nil{
let school = School(id: data["id"].int!, name: data["name"].string!)
self.arraySchools.append(school)
}
}
}
print(self.arraySchools)
}, completionFailure: {(response) in
if let responseValue: AnyObject = response.result.value as AnyObject? {
let jsonResponse = JSON(responseValue)
print(jsonResponse)
AlertView.showAlert(view: self, message: "Error")
}
})
}
API返回:
{
"data":{
"0":{
"id":793,
"name":"1",
"default":false
},
"1":{
"id":3,
"name":"2",
"default":false
},
"2":{
"id":792,
"name":"28",
"default":false
},
"3":{
"id":5,
"name":"3",
"default":false
},
"4":{
"id":9,
"name":"6",
"default":false
},
"5":{
"id":795,
"name":"793",
"default":false
},
"6":{
"id":11,
"name":"8",
"default":false
},
"7":{
"id":4,
"name":"aasdasdasd",
"default":false
},
"8":{
"id":23,
"name":"Abbotsleigh",
"default":true
},
"9":{
"id":24,
"name":"Academies Australiasia",
"default":true
},
"10":{
"id":785,
"name":"Acme labs",
"default":false
},
"11":{
"id":25,
"name":"Airds High School",
"default":true
},
"12":{
"id":26,
"name":"Al Amanah College",
"default":true
},
"13":{
"id":27,
"name":"Albion Park High School",
"default":true
}
},
"links":[
]
}