時間字符串轉換成秒蟒蛇

Question

我需要轉換成以下格式seconds.I給定的時間值的字符串現在用python2.6

如：

1.'00:00:00,000' -> 0 seconds 

2.'00:00:10,000' -> 10 seconds 

3.'00:01:04,000' -> 64 seconds 

4. '01:01:09,000' -> 3669 seconds 

我需要使用正則表達式來做到這一點？我試圖用時間模塊，但是time.strptime('00:00:00,000','%I:%M:%S')扔

ValueError: time data '00:00:00,000' does not match format '%I:%M:%S' 

有人能告訴我，這可怎麼解決呢？

編輯：

我覺得

pt =datetime.datetime.strptime(timestring,'%H:%M:%S,%f') 
total_seconds = pt.second+pt.minute*60+pt.hour*3600 

給出正確value..I用錯模塊

Answer 1

解析對於Python 2.7：

>>> import datetime 
>>> import time 
>>> x = time.strptime('00:01:00,000'.split(',')[0],'%H:%M:%S') 
>>> datetime.timedelta(hours=x.tm_hour,minutes=x.tm_min,seconds=x.tm_sec).total_seconds() 
60.0 

Answer 2

它看起來像你願意剝離幾分之一秒..問題是你不能用'00'作爲小時，%I

>>> time.strptime('00:00:00,000'.split(',')[0],'%H:%M:%S') 
time.struct_time(tm_year=1900, tm_mon=1, tm_mday=1, tm_hour=0, tm_min=0, tm_sec=0, tm_wday=0, tm_yday=1, tm_isdst=-1) 
>>> 

Answer 3

總有手工

>>> import re 
>>> ts = ['00:00:00,000', '00:00:10,000', '00:01:04,000', '01:01:09,000'] 
>>> for t in ts: 
...  times = map(int, re.split(r"[:,]", t)) 
...  print t, times[0]*3600+times[1]*60+times[2]+times[3]/1000. 
... 
00:00:00,000 0.0 
00:00:10,000 10.0 
00:01:04,000 64.0 
01:01:09,000 3669.0 
>>> 

Answer 4

多一點Python的方式，我認爲應該是：

timestr = '00:04:23' 

ftr = [3600,60,1] 

sum([a*b for a,b in zip(ftr, map(int,timestr.split(':')))]) 

輸出是263Sec。

我想查看是否有人可以進一步簡化它。

Answer 5

要獲得timedelta()，你應該減去1900-01-01：

>>> from datetime import datetime 
>>> datetime.strptime('01:01:09,000', '%H:%M:%S,%f') 
datetime.datetime(1900, 1, 1, 1, 1, 9) 
>>> td = datetime.strptime('01:01:09,000', '%H:%M:%S,%f') - datetime(1900,1,1) 
>>> td 
datetime.timedelta(0, 3669) 
>>> td.total_seconds() # 2.7+ 
3669.0 

%H以上意味着輸入是不到一天的時間，支持時間差超過一天：

>>> import re 
>>> from datetime import timedelta 
>>> td = timedelta(**dict(zip("hours minutes seconds milliseconds".split(), 
...       map(int, re.findall('\d+', '31:01:09,000'))))) 
>>> td 
datetime.timedelta(1, 25269) 
>>> td.total_seconds() 
111669.0 

要在Python 2.6上效仿.total_seconds()：

>>> from __future__ import division 
>>> ((td.days * 86400 + td.seconds) * 10**6 + td.microseconds)/10**6 
111669.0 

Answer 6

沒有進口

time = "01:34:11" 
sum(x * int(t) for x, t in zip([3600, 60, 1], time.split(":")))